Easy
(g o f)(-5)=g(f(-5))
first evaluate f(-5), then input the result into g(x)
f(-5)=-2(-5)-7
f(-5)=10-7
f(-5)=3
g(3)=-4(3)+6
g(3)=-12+6
g(3)=-6
(g o f)(-5)=-6
I need points so I can solve my math, I have a 62 and need to save my grade I hope you get your answer, I'm so sorry....
Answer:
x - 99 ≤ -104 → 2nd line
x - 51 ≤ -43 → 1st line
150 + x ≤ 144 → 4th line
75 < 69 - x → 3rd line
Step-by-step explanation:
Ugh! Wow, this is going to be tedious, thanks alot, bro (jk, I got your back).
x - 99 ≤ -104
+ 99 + 99
x ≤ -5
There should be a line going from -5 to negative infinity (AKA the left) with a FILLED circle. So, the second one is correct.
x - 51 ≤ -43
+ 51 + 51
x ≤ 8
There should be an arrow with a FILLED circle going to negative infinity (AKA the left). So, the first one is correct.
I'm going to take a shortcut and notice that one of the lines has a filled circle while the other one has an empty circle. So the empty circle must relate to the question without a ≤ or ≥, but with a < or >. We see that 75 < 69 doesn't have ≤ or ≥ but a '<.' So this one must have the empty circle, which is on line 3. The last equation has to be on line 4.
Answer:
21
Step-by-step explanation:
You do the parentheses first, so 27/9 = 3
10-3 = 7
3 * 7 = 21
The probabilities are:
- P(red) = 5/24
- P(orange) = 0
- P(blue) = 1/3
- P(not green)= 17/24
- P(green or black) = 11/24
- P(not yellow) = 1.
<h3>
How to find the probabilities?</h3>
The probability of getting a particular color of marble, is given by the quotient between the number of marbles of that color and the total number of marbles.
Here we have:
- 5 red marbles.
- 7 green marbles.
- 4 black marbles.
- 8 blue marbles.
So the total number is 5 + 7 + 4 + 8 = 24.
Then:
- P(red) = 5/24
- P(orange) = 0/24 = 0 (because there are 0 orange marbles).
- P(blue) = 8/24 = 1/3
- P(not green) = (24 - 7)/24 = 17/24
- P(green or black) = (4 + 7)/24 = 11/24
- P(not yellow) = 24/24 = 1 (because there aren't yellow marbles).
If you want to learn more about probability, you can read:
brainly.com/question/251701
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