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ipn [44]
3 years ago
10

I rlly need the answer to this asap thanks

Mathematics
1 answer:
Allisa [31]3 years ago
8 0
1st, 4th, and 5th 

7500 * 1.2
7500+1/5(7500)
7500+.2(7500)

I've always hated tenmarks, rip
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Please Help....................................
serg [7]
4^3*4^4 / 4^6 = 4^7 / 4^9 = 1/4^2
answer is C. 1 / 4^2
3 0
4 years ago
Simplify 112/63 in lowest terms
LuckyWell [14K]
16/9 is the answer hope this helps bye
8 0
4 years ago
Verify that each equation is an identity (1 - sin^(2)((x)/(2)))/(1+sin^(2)((x)/(2)))= (1+cosx)/(3-cosX)
Allisa [31]

Answer:

Given that we have;

sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }

By the application of the law of indices and algebraic process of adding a and subtracting a fraction from a whole number, we have;

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) }  =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

Step-by-step explanation:

An identity is a valid or true equation for all variable values

The given equation is presented as follows;

\dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

From trigonometric identities, we have;

sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }

\therefore sin^2 \left (\dfrac{x}{2} \right ) = \dfrac{1 - cos (x)}{2}

1 -  sin^2 \left (\dfrac{x}{2} \right ) = 1 - \dfrac{1 - cos (x)}{2} = \dfrac{2 - (1 - cos (x))}{2} = \dfrac{1 + cos (x))}{2}

1 +  sin^2 \left (\dfrac{x}{2} \right ) = 1 + \dfrac{1 - cos (x)}{2} = \dfrac{2 + 1 - cos (x))}{2} = \dfrac{3 - cos (x))}{2}

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) }  =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

3 0
3 years ago
PLEASE HELP HELP!!! PRECALC
brilliants [131]

Answer:

The base is 0.1

The base is less than 1 so the function is decreasing

The x intercept is (3,0)

Step-by-step explanation:

The base of a logarithm refers to the number that must be raised to the power of the number on the right hand side of the logarithmic equation in order to yield the number on the left hand side of the logarithmic equation. It is always written as a subscript below the log symbol. In this case, the base is 0.1.

When the base of a logarithm is less than 1, it means that the function is decreasing as is the case in this question.

Looking at the graph, the x axis is cut at the point (3,0). This is the x-intercept of the graph.

4 0
3 years ago
At Hank's Hobbies, a package of 16 model car tires sells for $11.52. and a package of 20 model car tires sells for $13.50. Which
Andru [333]

Answer:

The 20 model is cheaper.

Step-by-step explanation:

There would be 0.72 cents for each tire if you bought 16. If you buy 20, you pay 0.67 cents. Therefore the 20 pach is cheaper.

3 0
3 years ago
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