<span>(6c2) * (10c6) * (3c2)
Multiply
60c8 * 3c2
Multiply again
Final Answer: 180c10</span>
Answer:
67.4 mph
distance~337
rate~67.4 mph
time~5 hours
Step-by-step explanation:
hope this helps
Answer:
A) Dimensions;
Length = 20 m and width = 10 m
B) A_max = 200 m²
Step-by-step explanation:
Let x and y represent width and length respectively.
He has 40 metres to use and he wants to enclose 3 sides.
Thus;
2x + y = 40 - - - - (eq 1)
Area of a rectangle = length x width
Thus;
A = xy - - - (eq 2)
From equation 1;
Y = 40 - 2x
Plugging this for y in eq 2;
A = x(40 - 2x)
A = 40x - 2x²
The parabola opens downwards and so the x-value of the maximum point is;
x = -b/2a
Thus;
x = -40/2(-2)
x = 10 m
Put 10 for x in eq 1 to get;
2(10) + y = 40
20 + y = 40
y = 40 - 20
y = 20m
Thus, maximum area is;
A_max = 10 × 20
A_max = 200 m²
Answer:
Therefore,
The actual area of the basketball court if the scale drawing is
11.75 inches by 6.25 inches is
Step-by-step explanation:
Given:
Drawing Scale of a basketball court,
1 inch = 8 feet
To Find:
Actual area of the basketball court if the scale drawing is
11.75 inches by 6.25 inches = ?
Solution:
Scale is given as
1 inch = 8 feet
Therefore actual length and width in feet will be,
Now Area of Court is shape of Rectangle,
Substituting the values we get
Therefore,
The actual area of the basketball court if the scale drawing is
11.75 inches by 6.25 inches is
