This is a quadratic equation with a general equation of ax^2 + bx + c.
The quadratic formula can help to get the roots of the equation. We know the highest degree of that equation is 2; so there will be also two roots.
The quadratic formula is
x = [-b ± √(b^2 - 4ac)] / 2a
With a = 1, b = 7, c = 2,
x = {-7 ± √[(7)^2 - 4(1)(2)]} / 2(1) = (-7 ± √41) / 2
So the two roots are
x1 = (-7 + √41) / 2 = -0.2984
x2 = (-7 - √41) / 2 = 0.2984
This is also another way of factorizing the equation
(x + 0.2984)(x + 0.2984) = x^2 + 7x + 2
Yes, for fractions you can multiply the denominator by the numerator. For square roots you can use the square root button.
Answer:
y = 5/8 x -2
Step-by-step explanation:
Given that the slope of the line, m=5/8, which passes through the point (-8,-7).
Let the equation of the line be y=mx+c
where m is the slope of the line and c is a constant.
As m=5/8, so the equation of line become
y= 5/8x+c
As the line passes through the point (-8,-7), so putting y= -7 and x= -8, we have
-7 = 5/8(-8)+c
-7 = -5 + c
c= -7 + 5
c= -2
On putting the value of c, the equation of line become
y=5/8 x -2
Hence, the equation of the line is y = 5/8 x -2.
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Answer:
then what?
Step-by-step explanation:
do we have to find the angle?
all I know is every right triangle is equal to 90°
