I wrote the steps down, hopefully you understand them and the answer is on the lower right corner.
A tautology will have an infinite number of solutions, as it is true for all possible values of the variable by definition.
Example: 3(x+2) = 3x+6
All other linear equations in one variable will have one solution, which may include values that are undefined or indeterminate.
Examples:
... 3x-2 = 7 . . . solution is x=3
... x = 0/0 . . . . solution is an indeterminate number
... x = 1/0 . . . . solution is undefined
B.
D.
D.
4th: 1/12 and or 1/3
Coloumn A.
1.A
2.C
3.C
4.B
Answer:
700
Step-by-step explanation:
I think you mean "Hundred", not "Hundredth", since there is no hundredth in this problem.
Answer:
A
Step-by-step explanation:
The sequence of positive odd numbers is
1, 3, 5, 7, ......
This is an arithmetic sequence with common difference d
d = 3 - 1 = 5 - 3 = 7 - 5 = 2
The sum to n terms of an arithmetic sequence is
=
[2a + (n - 1)d ]
where a is the first term
here a = 1, d = 2, n = 12, hence
=
[1 + (11 × 2) ]
= 6 [ 2 + (11 × 2) ]
= 6 × 24 = 144 → A