We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students

To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
Since we are not given any information about the proportion, we will assume the sample proportion to be 0.50
so,
p = 0.50
The Error is 10% percentage point. This means that on either side of the population proportion the error is 5% so E = 0.05
z = 1.645 (Z value for 90% confidence interval)
The margin of error for population proportion is calculated as:
This means 271 students should be included in the sample
The answer is TRUE. The parallelogram must be a rectangle
Answer:
x= 1 or x=7
Step-by-step explanation:
2 x 2− 16 x + 14 =0
2 (x−1) (x−7)=0
x−1=0 or
x−7=0
x=1 or x=7
Answer:
Step-by-step explanation:
<u>Simplify the numerator:</u>
- 1/x² + 2/y =
- y/(x²y) + 2x²/(x²y) =
- (2x² + y)/(x²y)
<u>Simplify the denominator:</u>
- 5/x - 6/y² =
- 5y²/(xy²) - 6x/(xy²) =
- (5y² - 6x) / (xy²)
<u>Simplify the fraction:</u>
- (2x² + y)/(x²y) ÷ (5y² - 6x) / (xy²) =
- (2x² + y)/(x²y) × xy² / (5y² - 6x) =
- y(2x² + y) / x(5y² - 6x)