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zvonat [6]
3 years ago
5

Today encoding scheme has taken over ascII by what

Computers and Technology
1 answer:
harkovskaia [24]3 years ago
7 0
I do not know, i really hope you dont fail!!!!!!!!!
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A compression scheme for long strings of bits called run-length encoding is described as follows: Rather than record each 0 and
Musya8 [376]

Answer: (B) Lossless compression

Explanation:

 According to the question, the given technique is the example of the lossless compression. The lossless compression is one of the technique that decompress the data into the original data form without any type of losses.

The lossless compression is the technique that usually compress the data, text and the databases. This technique also improve the compression rate helps in reconstruct the original data. It is used in various types of encoding methods, GNU tool and zip file.

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3 years ago
What software is my teacher using to do this and how can i stop her from doing this
aliina [53]

Answer:

I’m not sure if you can only teachers can acess that

Explanation:

7 0
3 years ago
Read 2 more answers
Create union floatingPoint with members float f, double d and long double x. Write a program that inputs values of type float, d
Kitty [74]

Answer:

Here the code is given as follows,

#include <stdio.h>

#include <stdlib.h>

union floatingPoint {

float floatNum;

double doubleNum;

long double longDoubleNum;

};

int main() {

union floatingPoint f;

printf("Enter data for type float: ");

scanf("%f", &f.floatNum);

printf("\nfloat %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

printf("\n\nEnter data for type double: ");

scanf("%lf", &f.doubleNum);

printf("float %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

printf("\n\nEnter data for type long double: ");

scanf("%Lf", &f.longDoubleNum);

printf("float %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

return 0;

}

5 0
3 years ago
Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con
icang [17]

Answer:

<em>The programming language is not stated;</em>

<em>I'll answer using C++</em>

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

 cout<<"Invalid Inputs";

}

else {

 if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else {

  cout<<"Not Right Angled";

 }

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

<em> if(side1<=0 || side2 <= 0 || side3 <= 0) { </em>

<em>  cout<<"Invalid Inputs"; </em>

<em> } </em>

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

<em>if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

If none of the above conditions is true, then the triangle is not a right angles triangle

<em>  else { </em>

<em>   cout<<"Not Right Angled"; </em>

<em>  } </em>

}

return 0;

Download cpp
4 0
3 years ago
The word blog is made from what two terms?
mafiozo [28]
• web + log = blog •
3 0
3 years ago
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