Answer:
The correct answer to the following question will be "Local mapping".
Explanation:
- A data independence standard in global DBMSs where questions can be constructed without understanding the local formats. Knowledge of quotas of pieces and components is however important.
- With the transparency of local mapping, the user wants to determine both fragment location and name of data items, keeping in mind any replication that may occur.
- This is clearly a more complicated and time-consuming question for all the users to answer than the first. A program that only offers it the amount of transparency would be unlikely to be satisfactory to later part-users.
Therefore, "Local mapping" is the right answer.
C- are only occasionally affected by the decisions made by other teams
explanation
idk
Answer: 115 miles a month
Explanation:
460/4
which equals
<em><u>115 miles per month</u></em>
Answer:
(10^6 + 9.9)
Explanation:
Given:
Total number of machine instructions = 1000
Number of page fault in 100 instructions = 1
Number of page faults in 1000 instructions = 10
Time to serve one page fault = 100 milliseconds
Time to serve ten page faults = 100*10 milliseconds = 1000 milliseconds = 10^6 Microseconds
Number of instructions without any page fault = 1000 - 10 = 990
Time required to run 1000 instructions = 10 Microseconds
So, time required to run 990 instructions = (10*(990/1000)) Microseconds = 9.9 Microseconds
So, the total time required to run the program = (10^6 + 9.9) Microseconds
Shuffle (A[1..m], B[1..n], C[1..m+n]):
Shuf[0, 0] ← True
for j ← 1 to n
Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])
for i ← 1 to n
Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])
for j ← 1 to n
Shuf[i, j] ← False
if A[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]
if B[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]
return Shuf[m, n]
The algorithm runs in O(mn) time.
