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andrey2020 [161]
3 years ago
7

What is the difference of rational expressions below 6x/x-3 - 5/x

Mathematics
1 answer:
swat323 years ago
5 0

Answer:

$  \frac{6x^2-5x+15 }{x^2-3x} $

Step-by-step explanation:

$\frac{6x}{x-3} -\frac{5}{x} $

$\frac{6x(x)}{x(x-3)} -\frac{5(x-3)}{x(x-3)} $

$\frac{6x^2}{x^2-3x} -\frac{5x-15}{x^2-3x} $

$  \frac{6x^2-5x+15 }{x^2-3x} $

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