What is the difference of rational expressions below 6x/x-3 - 5/x

Mathematics

1 answer:

swat323 years ago

5 0

Answer:

$\frac{6x^2-5x+15 }{x^2-3x}$

Step-by-step explanation:

$\frac{6x}{x-3} -\frac{5}{x}$

$\frac{6x(x)}{x(x-3)} -\frac{5(x-3)}{x(x-3)}$

$\frac{6x^2}{x^2-3x} -\frac{5x-15}{x^2-3x}$

$\frac{6x^2-5x+15 }{x^2-3x}$

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Define x :
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Let the width be x
Width = x
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Formula :
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Perimeter = 2 (Length + Width)

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Find Length and Width :
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Width = x = 6mm
Length = 4x + 7 = 4(6) + 7 = 31mm

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Answer: The length is 31mm and its width 6mm.
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