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oksian1 [2.3K]
4 years ago
12

What is 8 3/5 times 8 3/5

Mathematics
2 answers:
olga_2 [115]4 years ago
8 0
8 (3/5) = (43/5)
So the problem becomes what does
(43/5) * (43/5) equal?

= 1,849 / 25
=73 + (24/25)


jok3333 [9.3K]4 years ago
5 0
The first step to solving this question is to convert the first mixed number to an improper fraction
\frac{43}{5} × 8\frac{3}{5}
now convert the second mixed number to an improper fraction
\frac{43}{5} × \frac{43}{5}
now multiply the fractions together to get your answer
\frac{1849}{25}
the correct answer to your question is going to be \frac{1849}{25} ,, which can also be simplified as 73 \frac{24}{25} ,, 73.96,, or (\frac{43}{5})²
let me know if you have any further questions
:)
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<span>T (2-5),(-1+5) = T -3,4 

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A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
IrinaVladis [17]

Answer:

720 ways

Step-by-step explanation:

Generally, combination is expressed as;

                                  ^{n} C_{r} = \frac{n!}{r!(n-r)!}

The question consists of 9 multiple-choice questions and examinee must answer 7 of the multiple-choice questions.

                                   ⇒ ⁹C₇ =\frac{9!}{7!(9-7)!}

                                        =\frac{9!}{7!(2)!}

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The question consists of 6 open-ended problems and examinee must answer 3 of the open-ended problems.

                                    ⇒ ⁶C₃ =\frac{6!}{3!(6-3)!}

                                         =\frac{6!}{3!(3)!}

                                         = 20

Combining the two combinations to determine the number of ways the questions and problems be chosen if an examinee must answer 7 of the multiple-choice questions and 3 of the open-ended problem.

                                        ⁹C₇ × ⁶C₃

                                       = 36 × 20

                                       = 720 ways  

3 0
3 years ago
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