Is 10(x-2)=5(2x-4) infinitely many or no solution
1 answer:
You might be interested in
9514 1404 393
Answer:
x = -4/3y² -40/3y -103/3
x = -4/3(y +5)² -1
Step-by-step explanation:
Solve for x.
x = (4y² +40y +103)/(-3)
x = -4/3y² -40/3y -103/3 . . . . 'standard form' in the US
__
Taking our clues from the graph*, we can write the vertex form equation as ...
x = -4/3(y +5)² -1 . . . . . . 'standard form' in other places
_____
* The vertex is (-1, -5), so for some leading coefficient, the equation will be ...
x = a(y -(-5))² +(-1) = a(y +5)² -1
The value of 'a' is the scale factor. Here, that is the difference between the parabola value (x = -2 1/3) and the vertex value (x = -1) one unit away from the vertex.
I've attached the complete question withe the 2 quadrilaterals.
Answer:
Jennifer is not correct because equal angles alone is not a proof of congruency.
Step-by-step explanation:
Now, in test for congruence, we use any of the following criteria;
SSS: Side - Side - Side
SAS: Side - Angle - Side
ASA: Angle - Side - Angle
AAS: Angle - Angle - Side
RHS: Right angle - Hypotenuse - Side
The assumption in the question is that all the angles are equal to determine that the quadrilaterals are congruent.
However, we don't use AAA(Angle - Angle - Angle theorem) as a congruence proof because it's very possible to have all the internal angles equal and yet all the corresponding sides don't have the same length.
Thus, Jeniffer is not correct.
