I hope this helps you
Q and R complimentary
6x+20+2x=180
8x=160
x=20
Answer:
See below, please.
Step-by-step explanation:
![45 \div ( \frac{3}{4} ) = 60](https://tex.z-dn.net/?f=45%20%5Cdiv%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%20%3D%2060)
Hence, the number is 60.
Answer:
if this is division it's 1.2.
Step-by-step explanation:
just divide it of its division if not sorry
<h2><u>
Answer with explanation</u>
:</h2>
Let
be the average life of light bulbs.
As per given , we have
Null hypothesis : ![H_0 : \mu =5400](https://tex.z-dn.net/?f=H_0%20%3A%20%5Cmu%20%3D5400)
Alternative hypothesis : ![H_a : \mu >5400](https://tex.z-dn.net/?f=H_a%20%3A%20%5Cmu%20%3E5400)
Since
is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.
Formula for Test statistic : ![z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B%5Coverlien%7Bx%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
where, n= sample size
= sample mean
= Population mean
=population standard deviation
For
, we have
![z=\dfrac{5483-5400}{\dfrac{500}{\sqrt{95}}}=1.61796786124\approx1.6180](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B5483-5400%7D%7B%5Cdfrac%7B500%7D%7B%5Csqrt%7B95%7D%7D%7D%3D1.61796786124%5Capprox1.6180)
Using z-value table , Critical one-tailed test value for 0.06 significance level :
![z_{0.06}=1.5548](https://tex.z-dn.net/?f=z_%7B0.06%7D%3D1.5548)
Decision : Since critical z value (1.5548) < test statistic (1.6180), so we reject the null hypothesis .
[We reject the null hypothesis when critical value is less than the test statistic value .]
Conclusion : We have enough evidence at 0.06 significance level to support the claim that the new filament yields a longer bulb life
Linear because there is a constant change (+3)