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Mice21 [21]
2 years ago
9

How to decide if a point is on a parabola

Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
5 0

Answer:

All you need is the coordinates of your point (x,y) as well as the function of your parabola (y=x^2 for example).

Then, replace the x and y from the function by the coordinates of your point.

If you end up with the same number on both sides of the equation, then the point is on your curve. If not, it isn't on your curve.

For example, we want to know if K(3,8) is on the parabola y=x^2–1.

8=3^2–1

8=8

So the point K is on the parabola.

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Blizzard [7]

Answer:

1:6 = 7:42

Step-by-step explanation:

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2 years ago
Make a function table to represent his total savings for 2,4,6,8 and 10 months.
OlgaM077 [116]
Well, let's say that bananas cost $1.60 per pound. That means that at step 0 the value is 0, at step 1 the value is$1.60, at step 2 the value is $$3.20 and so on. To make a table from this we'd need two columns and four rows. On the top row we right step followed by amount. In the step column, we list the numbers 0-2. In the amount column we list 0, $1.60, and $3.20. In the end, a function table looks like this:
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3 years ago
Find the exact value of tan A in simplest radical form
AlladinOne [14]

Answer:

12.68 de

Step-by-step explanation:

8 0
2 years ago
I kind of understand this question, but I'm not sure how to answer it directly, can someone help please.
nordsb [41]
So here we use the pythagorean theorem which is a2 + b2 = c2 (“a” squared times “b” squared equals “c” squared) the length from calvins house to the intersection is “a” and the length from phoebes house to the intersection is “b” so in order to find out the length of “c” (calvins house to phoebes house) we need to use the pythagorean theorem

a2 275x275=75,625

b2 113x113 = 12,769

so now that we have figured out what a2 and b2 are let’s add them

75,625 + 12,769 = 88,394

now since we only need to find out the length and not the area we need to find the square root of 88,394

the square root of 88,394 is 297.311 (i cut off the decimal after three places)

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5 0
3 years ago
HELP i’m having trouble with my homework assignments
Aleksandr-060686 [28]

Answer:

Collin: about $401 thousand

Cameron: about $689 thousand

Step-by-step explanation:

A situation in which doubling time is constant is a situation that can be modeled by an exponential function. Here, you're given an exponential function, though you're not told what the variables mean. That function is ...

P(t)=P_0(2^{t/d})

In this context, P0 is the initial salary, t is years, and d is the doubling time in years. The function gives P(t), the salary after t years. In this problem, the value of t we're concerned with is the difference between age 22 and age 65, that is, 43 years.

In Collin's case, we have ...

P0 = 55,000, t = 43, d = 15

so his salary at retirement is ...

P(43) = $55,000(2^(43/15)) ≈ $401,157.89

In Cameron's case, we have ...

P0 = 35,000, t = 43, d = 10

so his salary at retirement is ...

P(43) = $35,000(2^(43/10)) ≈ $689,440.87

___

Sometimes we like to see these equations in a form with "e" as the base of the exponential. That form is ...

P(t)=P_{0}e^{kt}

If we compare this equation to the one above, we find the growth factors to be ...

2^(t/d) = e^(kt)

Factoring out the exponent of t, we find ...

(2^(1/d))^t = (e^k)^t

That is, ...

2^(1/d) = e^k . . . . . match the bases of the exponential terms

(1/d)ln(2) = k . . . . . take the natural log of both sides

So, in Collin's case, the equation for his salary growth is

k = ln(2)/15 ≈ 0.046210

P(t) = 55,000e^(0.046210t)

and in Cameron's case, ...

k = ln(2)/10 ≈ 0.069315

P(t) = 35,000e^(0.069315t)

5 0
3 years ago
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