In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, wha

Question

tensa zangetsu [6.8K]

3 years ago

12

In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, wha

t is the probability you will choose a consonant and then a vowel?

Mathematics

2 answers:

a_sh-v [17] · Answer 1 · 2022-02-03T20:01:34+03:00

a_sh-v [17]3 years ago

7 0

28+12=40

$P(C,V)=\frac{12}{40} \times \frac{28}{40}\\\\ = \frac{12 \ \div \ 4}{40 \ \div \ 4} \times \frac{28 \ \div \ 4}{40 \ \div \ 4} \\\\ = \frac{3}{10} \times \frac{7}{10} \\\\ =\frac{21}{100}=0.21$

Answer:
$P(C,V)=0.21$

ohaa [14] · Answer 2 · 2022-02-03T17:38:31+03:00

ohaa [14]3 years ago

3 0

With replacement:

P(C,V)=(12/40)(28/40)

P(C,V)=336/1600

P(C,V)=21/100