Question

In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, what is the probability you will choose a consonant and then a vowel?

Answer 1

28+12=40

$P(C,V)=\frac{12}{40} \times \frac{28}{40}\\\\ = \frac{12 \ \div \ 4}{40 \ \div \ 4} \times \frac{28 \ \div \ 4}{40 \ \div \ 4} \\\\ = \frac{3}{10} \times \frac{7}{10} \\\\ =\frac{21}{100}=0.21$

Answer:
$P(C,V)=0.21$

Answer 2

With replacement:

P(C,V)=(12/40)(28/40)

P(C,V)=336/1600

P(C,V)=21/100