Question

to find the area of a trapezoid dylan uses the formula A=1/2 (B1+B2)h the bases have lengths of 3.6 cm and 12 1/3 cm. the height of the trapezoid is cube root of 5 The area of the trapezoid is irrational because

Answer 1

Answer:

It is irrational because it can not be represented as a fraction of two integers

Step-by-step explanation:

Given

$B_1 = 3.6$

$B_2 = 12\frac{1}{3}$

$H = \sqrt[3]5$

Required

Why is the area irrational?

First, we need to calculate the area

$Area = \frac{1}{2}(B_1 + B_2) * H$

$Area = \frac{1}{2}(3.6 + 12\frac{1}{3}) * \sqrt[3]5$

$Area = \frac{1}{2}(3.6 + \frac{37}{3}) * 17100$

$Area = \frac{1}{2}(\frac{10.8+37}{3}) * 1.710$

$Area = \frac{1}{2}(\frac{47.8}{3}) * 1.7100$

$Area = \frac{47.8}{6} * 1.7100$

$Area = \frac{47.8* 1.7100}{6}$

$Area = \frac{81.738}{6}$

$Area = 13.623$

It is irrational because it can not be represented as a fraction of two integers