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Makovka662 [10]
4 years ago
5

Which graph represents the PARENT function of y = x2 + 3?

Mathematics
1 answer:
Tpy6a [65]4 years ago
5 0
The graph of a parabola ( x^2)

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Can anyone help me with question number 3
ira [324]
The answer is: There are 595 calories in a banana split 

To find this we first need to set up our equation: 

80= \frac{1}{7}x-5, where x= calories in a banana split


85= \frac{1}{7}x----------------Add 5 to both sides

595=x-------------------Multiply 7 to both sides to get rid of the fraction

So, there are 595 calories in a banana split

Hope this helps! :)
7 0
3 years ago
The coffee counter charges ?"$11.00" per pound for kenyan french roast coffee and ?"$13.00" per pound for sumatra coffee. How mu
zloy xaker [14]

Answer: The answer is 13 ponds of each type should be used.

Step-by-step explanation:  Given that the coffee counter charges $11.00 per pound for kenyan french roast coffee and $13.00 per pound for sumatra coffee. We are to find the quantity of each type that should be used to make a 26 pound blend that sells for $12.00 per pound.

Let 'x' pound and 'y' pound of  kenyan french roast coffee and sumatra coffee be used in the mixture of 26 pound.

So, we have

x+y=26,~~~~~~~~~~~~~~~~~~~~~~(A)\\\\11x+13y=12\times 26.~~~~~~~~~~(B)

Multiplying equation (A) by 11 and subtracting from equation (B), we have

13y-11y=12\times26-11\times26\\\\\Rightarrow 2y=26\\\\\Rightarrow y=13,

and from equation (A),

x=26-13=13.

Thus, 13 pounds of each type of coffee should be used.

8 0
3 years ago
Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​
insens350 [35]

Answer:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

Step-by-step explanation:

Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

p(x) = \frac{(x -3)(x + 1)}{x+2}

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

x -> -2^{-} Say x = -3

p(x) = \frac{(x -3)(x + 1)}{x+2}

p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

x->-2^{-}, p(x)->-\infty

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: x>-2

Say x = -2.1

p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

x->-2^{+}, p(x)->-\infty

So, the behavior is:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

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