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3 years ago

I had problem in these questions. Can anyone help me please?

Mathematics

1 answer:

Lyrx [107]3 years ago

5 0

Use google that my advice

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The distance around the school track is 0.25 mile. It takes Maribeth 5.1 minutes to run 2 laps around the school track. At that

BabaBlast [244]

Answer:

10.2 minutes

Step-by-step explanation:

1 lap= 1/4 mile

2 laos= 1/2 mile

5.1 x 2= 10.2 minutes

7 0

2 years ago

Enlargement or reduction?

djyliett [7]

Answer:

Reduction

Step-by-step explanation:

so, the blue shape's letters are E, F, G, H and I.

the green shape's letters are E', F', G', H', and I'.

the letters with the ' are the ones that are after the origianal.

:) hope i helped

4 0

2 years ago

Read 2 more answers

Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.

Bas_tet [7]

Answer:

The function touches the damping factor

at x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

The x-intercept of f(x) is

at x= $n\pi$

Step-by-step explanation:

Given function is f(x)= $e^{-3x} sin(x)$ and damping factor as y= $e^{-3x}$ and y= $(-1)e^{-3x}$

To find when function touches the damping factor:

For f(x)= $e^{-3x} sin(x)$ and y= $e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=e^{-3x}$

$sin(x)=1$

x= $\frac{(4n-3)\pi}{2}$

For f(x)= $e^{-3x} sin(x)$ and y= $(-1)e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=(-1)e^{-3x}$

$sin(x)=(-1)$

x= $\frac{(4n-1)\pi}{2}$

Therefore, The function touches the damping factor x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

To find x-intercept of f(x):

For x-intercept, y=0

f(x)= $e^{-3x} sin(x)$

y= $e^{-3x} sin(x)$

$e^{-3x} sin(x)=0$

Hence, $e^{-3x}$ is always greater than zero.

Therefore, $sin(x)=0$

x= $n\pi$

Thus,

The x-intercept of f(x) is at x= $n\pi$

7 0

3 years ago

I need help on this and the person who answer this correctly gets a BRANLIST(answer if you know)

denpristay [2]

Answer:

14.425

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What is the tangent of an equal to

elena-s [515]

The tangent of x is defined to be its sine divided by its cosine: tan x = sin x cos x . The cotangent of x is defined to be the cosine of x divided by the sine of x: cot x = cos x sin x .

3 0

3 years ago