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vivado [14]
3 years ago
8

Please help me I need this done I need someone who will SHOW WORK and complete all the questions for 15 points please help me if

you can!

Mathematics
2 answers:
Jet001 [13]3 years ago
5 0

Answer:

1.1995

2.114.4

3.270

Step-by-step explanation:

1. Multiply the length and width

2. Multiply 14.3*8

3. Multiply 15*36 and divide the product by 2

to find the area of a rectangle, multiplty length times width

for the area of a triangle, multiply the bottom of the triangle by the height and divide it by 2.

Studentka2010 [4]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

1a) Area of rectangle = L * W

A = 57*35 = 1995 in²

1b) A =L * W = 8 * 14.3 = 114.4 cm²

1c) Area of Δ =1/2 base x height

Height is always perpendicular to the base!!!

base = 36; height = 15

A of Δ = (1/2) * 36 * 15 =18*15 = 270 m²

1d) Area of Δ =1/2 base x height

 base = 27.3; height =  16.8

A of Δ = (1/2) * 27.3 * 16.8 = 229.32 rounded to  final answer <u>229.3 in² !!!!</u>

1e)  Area of Δ =1/2 base x height

   base = 14; height = 9

A of Δ = (1/2) * 14 * 9 = 7 * 9 = 63 yd²

1e)  Area of Δ =1/2 base x height

   base =30 ; height = 40

In this case base also can be 40 and height 30 b/c it's right Δ

A of Δ = (1/2) * 30 * 40 = 15 * 40 =600 ft²

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cricket20 [7]

We need to evaluate the value of fraction \frac{j}{4}.

We also given j=12.

In order to evaluate the value of fraction \frac{j}{4}, we need to plug j=12.

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The manufacturer of a CD player has found that the revenue R​ (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com
AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

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The revenue function is given as:

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Equating the first derivative to zero, we get,

\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

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\dfrac{d^2(R(p))}{dp^2} < 0

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

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Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0
3 years ago
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