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enot [183]
3 years ago
6

(2x+1)(2x-1) find the product

Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0
Difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
recognize that

(2x+1)(2x-1)
(a+b)(a-b)
therefor
product is
(2x)^2-(1)^2=
4x^2-1
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Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco
ANTONII [103]

Answer:

(a) The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(b) The value of P (129 ≤ X ≤ 146) is 0.3462.

(c) The probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

Step-by-step explanation:

The random variable <em>X</em> is defined as the flight time between the two cities.

Since the random variable <em>X</em> denotes time interval, the random variable <em>X</em> is continuous.

(a)

The random variable <em>X</em> is Uniformly distributed with parameters <em>a</em> = 10 minutes and <em>b</em> = 154 minutes.

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(b)

Compute the value of P (129 ≤ X ≤ 146) as follows:

Apply continuity correction:

P (129 ≤ X ≤ 146) = P (129 - 0.50 < X < 146 + 0.50)

                           = P (128.50 < X < 146.50)

                           =\int\limits^{146.50}_{128.50} {\frac{1}{154-102}} \, dx

                           =\frac{1}{52}\times \int\limits^{146.50}_{128.50} {1} \, dx

                           =\frac{1}{52}\times (146.50-128.50)

                           =0.3462

Thus, the value of P (129 ≤ X ≤ 146) is 0.3462.

(c)

It is provided that a randomly selected flight between the two cities will be at least 3 minutes late, i.e. <em>X</em> ≥ 128 + 3 = 131.

Compute the value of P (X ≥ 131) as follows:

Apply continuity correction:

P (X ≥ 131) = P (X > 131 + 0.50)

                 = P (X > 131.50)

                 =\int\limits^{154}_{131.50} {\frac{1}{154-102}} \, dx

                 =\frac{1}{52}\times \int\limits^{154}_{131.50} {1} \, dx

                 =\frac{1}{52}\times (154-131.50)

                 =0.4327

Thus, the probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

6 0
3 years ago
(76-x+(17+4x)(25+7x)​
daser333 [38]
I believe this is correct

8 0
3 years ago
Read 2 more answers
How do i get the factor of 3p2-2p-5
tensa zangetsu [6.8K]
3p² - 2p - 5 = 0

3p² + 3p - 5p - 5 = 0

3p(p + 1) -5(p + 1) = 0

(3p - 5)(p + 1) = 0

p = 5/3 or -1

Hope this helps!
5 0
3 years ago
Read 2 more answers
What is the area of this figure?
sergiy2304 [10]

1.5 \times 3 = 4.5 \:  {(km)}^{2}

3 0
3 years ago
2. Factorizar: 3ax – 3ay – 2bx + 2by<br>help please :(
nekit [7.7K]

Answer:

There are no like terms.

Step-by-step explanation:

basically that is your answer you can not solve so it will be 3ax – 3ay – 2bx + 2by

7 0
2 years ago
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