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enot [183]
3 years ago
6

(2x+1)(2x-1) find the product

Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0
Difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
recognize that

(2x+1)(2x-1)
(a+b)(a-b)
therefor
product is
(2x)^2-(1)^2=
4x^2-1
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How do you solve 1-5+1×(4×4-31)×8
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Hey there!

In order to solve this, remember PEMDAS. First, start with solving whatever is in parentheses. Then, move on to exponents. Then, complete the multiplication and division. Lastly, add or subtract anything remaining. Omit any steps that aren't present. 

Parentheses: 

<span>1 – 5 + 1 × (4 × 4 – 31) × 8
</span>1 – 5 + 1 × (–15) × 8

Multiplication/Division (Left to Right):

1 – 5 + (–15) × 8
1 – 5 + (–120)
1 – 5 – 120

Addition/Subtraction (Left to Right):

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Your answer is –124. 

Hope this helped you out! :-)
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Given:

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