Question

Find in RxR the S.S of the following pair of equation

Answer 1

Answer:

(- 2, - 1 ), (2, 1 )

Step-by-step explanation:

Given the 2 equations

x - 2y = 0 → (1)

x² - y² = 3 → (2)

Rearrange (1) expressing x in terms of y by adding 2y to both sides

x = 2y → (3)

Substitute x = 2y into (2)

(2y)² - y² = 3, that is

4y² - y² = 3

3y² = 3 ( divide both sides by 3 )

y² = 1 ( take the square root of both sides )

y = ± $\sqrt{1}$ = ± 1

Substitute these values into (3) for corresponding values of x

y = - 1 ⇒ x = 2(- 1) = - 2 ⇒ (- 2, - 1 )

y = 1 ⇒ x = 2(1) = 2 ⇒ (2, 1 )