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Dimas [21]
3 years ago
9

Find in RxR the S.S of the following pair of equation

Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0

Answer:

(- 2, - 1 ), (2, 1 )

Step-by-step explanation:

Given the 2 equations

x - 2y = 0 → (1)

x² - y² = 3 → (2)

Rearrange (1) expressing x in terms of y by adding 2y to both sides

x = 2y → (3)

Substitute x = 2y into (2)

(2y)² - y² = 3, that is

4y² - y² = 3

3y² = 3 ( divide both sides by 3 )

y² = 1 ( take the square root of both sides )

y = ± \sqrt{1} = ± 1

Substitute these values into (3) for corresponding values of x

y = - 1 ⇒ x = 2(- 1) = - 2 ⇒ (- 2, - 1 )

y = 1 ⇒ x = 2(1) = 2 ⇒ (2, 1 )

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Let's find the perimeter first by adding all the side lengths together. There are two missing side lengths, which we can find by taking the side opposite them and subtract the side behind the missing side from them.

I've attached a diagram showing how to find the side lengths.

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---

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