Answer:
32
Step-by-step explanation:
[1 , 6] = [1 , 3] + [3 , 6]
[6 , 3] = 10
[3 , 6] = -10
22 = [1 , 3] + (-10)
[1 , 3] = 22 + 10 = 32
Answer: No, Store A is charging $2.20 per rose while Store B is charging 2.166667 dollars per rose.
Step-by-step explanation:
11/5 = 2.2
(To check) 2.2 x 5 also equals $11
However, they are not selling roses at the same rate because if you were to do 2.2x6 it will equal 13.2.
13/6 = 2.166667
Answer:
Option E) 8000
Step-by-step explanation:
It is given in the question that the number of pencils and pens in a container A are 150 and 725.
Let the number of pens and pencils in container B are x and y.
As per statement " Ratio of the number of pencils to the number of pens is 2:3"
Equation will be ![\frac{x}{y}=\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D%5Cfrac%7B2%7D%7B3%7D)
Or
------(1)
Second statement says "If all pens and pencils of container B are placed in container A then ratio of pencils and pens would be 3:5"
Equation will be ![\frac{x+150}{y+725}=\frac{3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B150%7D%7By%2B725%7D%3D%5Cfrac%7B3%7D%7B5%7D)
5(x + 150) = 3(y + 725) [By cross multiplication]
5x + 750 = 3y + 2175
5x - 3y = 2175 - 750
5x - 3y = 1425 ------(2)
Now we put ![x=\frac{2}{3}y](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%7D%7B3%7Dy)
![5(\frac{2y}{3})-3y=1425](https://tex.z-dn.net/?f=5%28%5Cfrac%7B2y%7D%7B3%7D%29-3y%3D1425)
![\frac{10y}{3}-3y=1425](https://tex.z-dn.net/?f=%5Cfrac%7B10y%7D%7B3%7D-3y%3D1425)
![\frac{10y-9y}{3}=1425](https://tex.z-dn.net/?f=%5Cfrac%7B10y-9y%7D%7B3%7D%3D1425)
![\frac{y}{3}=1425](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B3%7D%3D1425)
y = 3×1425
y = 4275
Now we put y = 4275 in equation 1
![x=\frac{2}{3}(4275)](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%7D%7B3%7D%284275%29)
x = 2850
Now (x + y) = 2850 + 4275
= 7125
Now Total number of pen and pencils in container A and container B
= 150 + 725 + 7125
= 8000
Therefore, Option E) is the answer
Answer:24%
Step-by-step explanation:
6 divided by 25 is .24
The first two are given to you,
and
. Use the recursive formula to get the 3rd term; then use the 2nd and 3rd terms to get the 4th; and so on.
Since the <em>n</em>-th Lucas number is the sum of the previous two Lucas numbers, you have
![t_3 = t_2 + t_1 = 1 + 2 = 3](https://tex.z-dn.net/?f=t_3%20%3D%20t_2%20%2B%20t_1%20%3D%201%20%2B%202%20%3D%203)
![t_4 = t_3 + t_2 = 1 + 3 = 4](https://tex.z-dn.net/?f=t_4%20%3D%20t_3%20%2B%20t_2%20%3D%201%20%2B%203%20%3D%204)
![t_5 = t_4 + t_3 = 4 + 3 = 7](https://tex.z-dn.net/?f=t_5%20%3D%20t_4%20%2B%20t_3%20%3D%204%20%2B%203%20%3D%207)
![t_6 = t_5 + t_4 = 7 + 4 = 11](https://tex.z-dn.net/?f=t_6%20%3D%20t_5%20%2B%20t_4%20%3D%207%20%2B%204%20%3D%2011)
![t_7 = t_6 + t_5 = 11 + 7 = 18](https://tex.z-dn.net/?f=t_7%20%3D%20t_6%20%2B%20t_5%20%3D%2011%20%2B%207%20%3D%2018)
![t_8 = t_7 + t_6 = 18 + 11 = 29](https://tex.z-dn.net/?f=t_8%20%3D%20t_7%20%2B%20t_6%20%3D%2018%20%2B%2011%20%3D%2029)
![t_9 = t_8 + t_7 = 29 + 18 = 47](https://tex.z-dn.net/?f=t_9%20%3D%20t_8%20%2B%20t_7%20%3D%2029%20%2B%2018%20%3D%2047)