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3 years ago

14

What is, y = 3x² + 24x + 50 in vertex form. Please help !!

1 answer:

kvv77 [185]3 years ago

7 0

Answer:

y=3(x+4)²+2

Step-by-step explanation:

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Any help with this greatly appreciated.

Anestetic [448]

Put the equation in standard linear form.

$x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}$

Find the integrating factor.

$\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5$

Multiply both sides by $\mu$ .

$(t+5) x'(t) + x(t) = 5(t+5)e^{5t}$

Now the left side the derivative of a product,

$\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}$

Integrate both sides.

$(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt$

On the right side, integrate by parts.

$(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C$

Solve for $x(t)$ .

$\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}$

3 0

2 years ago

A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba

Ahat [919]

Answer:

$z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68$

Step-by-step explanation:

Information provided

n=100 represent the random sample taken

X=21 represent the number of bags overfilled

$\hat p=\frac{21}{100}=0.21$ estimated proportion of overfilled bags

$p_o=0.15$ is the value that we want to test

z would represent the statistic

Hypothesis

We need to conduct a hypothesis in order to test if the true proportion of overfilled bags is higher than 0.15.:

Null hypothesis: $p =0.7$

Alternative hypothesis: $p > 0.15$

The statistic for this case is:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

And replacing the info given we got:

$z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68$

5 0

3 years ago

Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o

wel

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is $x = 274 \ unites$

Step-by-step explanation:

From the question we are told that

The length of the vertical length is $x$

The length of the base leg is L = 330 + d units

The length of the bisecting line segment is h

The base angle is $\theta = 28^o$

The angle between d and line segment is $\theta_1 = 56^o$

For the first angle

$Tan \theta_1 = \frac{x}{d}$

=> $d = \frac{x}{Tan \theta _1}$

For the whole big triangle

$Tan \theta = \frac{x}{330 + d}$

=> $d = \frac{x}{Tan \theta } -330$

So equating the both d

$\frac{x}{Tan \theta _1} = \frac{x}{Tan \theta } -330$

Substitute values

$\frac{x}{Tan (56)} = \frac{x}{Tan (28) } -330$

$0.6745 x = 1.880x -330$

$1.20549 x = 330$

$x = 274 \ unites$

5 0

3 years ago

Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p

Mashcka [7]

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2

since 1/3 ≠ 2 there is no collision between the particles

6 0

3 years ago

Which expression represents 9 less than a number?

My name is Ann [436]

Answer:

x-9

Step-by-step explanation:

"Less than" switches the way of the expression.

If the "less than" was not there it would have been:

9-x

"Less" means subtract so you would subtract x from 9.

Hope this helped!

7 0

3 years ago

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