All categories

2 years ago

Number 11. Write 6^-3 =(1/216) correct answer will get brainliest

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

6 0

Answer:

-3 = log₆(1/216)

Step-by-step explanation:

Remember that when writing logarithm, the answer is:

exponent = log(base in subscript)y

also note that in exponential form, it looks like: y = b^x

Change

y = b^x = "(1/216) = 6^-3"

-3 = log₆(1/216)

-3 = log₆(1/216) is your answer

You might be interested in

Convert to the given unit. 65 m = cm

dedylja [7]

Answer:

65m = 6500 Cm.

Step-by-step explanation:

3 0

2 years ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0

2 years ago

Is the point (2,8) a solution of the equation y = 13x + 12? O Yes O No

vovikov84 [41]

Answer:

O No

Explanation:

Given equation: y = 13x + 12

To check if (2, 8) is a solution of the given equation.

Substitute x and y value in equation and check if it is true.

$\rightarrow y = 13x+12$

(x, y) = (2, 8)

$\rightarrow 8 = 13(2)+12$

simplify

$\rightarrow 8 = 38$

This following statement is false and hence (2, 8) is not a solution.

6 0

1 year ago

QUICK HELP!!! How manny differences can you spot? 8 6 7 4 3 5

Eduardwww [97]

Answer:

i can only see 3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A rectangular garden has a walkway around it. The area of the garden is 4(6.5x+3.5). The combined area of the garden and the w

alexdok [17]

Answer:The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

3 0

3 years ago