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3 years ago

Find each difference. Write in simplest form 7/8-5/8=

Mathematics

1 answer:

Ivanshal [37]3 years ago

5 0

7/8-5/8= 2/8 and if you reduce 2/8 by 2 it becomes 1/4. So 1/4 is your answer. Hope This Helps :D

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Nathan’s kite is in shape of a square. The area of the kite is 36 square feet. What is the perimeter, in feet, of Nathen’s kite

m_a_m_a [10]

6 I think

explanation
this is me trying fill in the 20 word required ment hope it helps

5 0

3 years ago

How many solutions does the following equation haves? -3x+9-2x=-12-5x

Mashcka [7]

Answer:

no solution

Step-by-step explanation:

-3x+9-2x=-12-5x\

-5x+5x=-12-9

0=-21

which is impossible.

4 0

2 years ago

How much money will you have if you started with $45 and put it in an account that earned 10% every year for 20 years

Veronika [31]

Probably it's all wrong
4.5 = 10 %If is the same then 4.5*20+45=135
If not then
FV=P(1+r)n45* (1+0.1)20 = 45*6.727=302.737

6 0

2 years ago

Complete the equation, by supplying the missing exponent.<br> m•n2•m3= m 11n2

MaRussiya [10]

Given:

Consider the given equation is:

$m^?\cdot n^2\cdot m^3=m^{11}\cdot n^2$

To find:

The missing exponent.

Solution:

Let x be the missing exponent. Then the given equation can be written as

$m^x\cdot n^2\cdot m^3=m^{11}\cdot n^2$

It can be rewritten as:

$(m^x\cdot m^3)\cdot n^2=m^{11}\cdot n^2$

$m^{x+3}\cdot n^2=m^{11}\cdot n^2$ $[\because a^ma^n=a^{m+n}]$

On comparing the coefficient of m, we get

$x+3=11$

$x=11-3$

$x=8$

Therefore, the value of the missing exponent is 8. So, the complete equation is $m^8\cdot n^2\cdot m^3=m^{11}\cdot n^2$ .

4 0

2 years ago

For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = $\sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}$

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

$cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }$

3 0

2 years ago