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bija089 [108]
3 years ago
11

Can someone help me in mathe ( the written blue are the answer choices )

Mathematics
1 answer:
Rudik [331]3 years ago
6 0
4) Here both smaller and larger triangle is "isosceles" in nature.
So, sum would be 180 with two equal sides.
66 + BDE + BED = 180
2 BDE = 180 - 66
BDE = 114 / 2
BDE = 57

<span>In short, Every four angles would be equal to 57

</span>5) A) 7
It is because it must be smaller than the longest side which is equal to 8

6) D) Yes, Because ∠C is congruent to ∠BED

Hope this helps!
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Help me show work please<br>​
GREYUIT [131]
Angle 4 would also be 135. the two on the top would add to 180, making a whole circle altogether that equals 360. so, you would do 180-135 = 45. angle 5 is 45. angle 7 would also be 135 because angle 4 and 7 are vertical angles.
5 0
3 years ago
1. Given the equation ​ ​y​ = -3​x​ + 2.5
valentina_108 [34]

Answer:

a. when x=1 so substitute 1 to any X in the given equation.

y=-3(1)+2.5

y=-3+2.5

y=-0.5

b.when x is -1.5 so substitute -1.5 to any x in the equation

y=-3(-1.5)+2.5

y=-4.5+2.5

y=-2

4 0
3 years ago
(Please help. I screenshot the question and choices D: )
vodka [1.7K]
The answer is yes, 1:8
8 0
3 years ago
Read 2 more answers
Fill in the missing work and justification for step 5 when solving 4(x + 1) = 8.
vlada-n [284]

4(x + 1) = 8

4x+4=8

4x=8-4

4x=4

x=4/4

x=1

5 0
3 years ago
Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred
Ksivusya [100]

1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


2. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


4. This ratio is equivalent to b^2=ce.


5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{BC}{BD}= \dfrac{AB}{BC}.


7. Knowing lengths you could state that \dfrac{a}{d}= \dfrac{c}{a}.


8. This ratio is equivalent to a^2=cd.


9. Now add results of parts 4 and 8:


b^2+a^2=ce+cd.


10. c is common factor, then:


b^2+a^2=c(e+d).


11. Since e+d=c you have a^2+b^2=c\cdot c=c^2.



7 0
3 years ago
Read 2 more answers
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