Question

PLEASE HELP! Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Check all that apply. 8(x2 + 2x + 1) = –3 + 8 x = –1 x = –1 8(x2 + 2x + 1) = 3 + 1 8(x2 + 2x) = –3

Answer 1

8(x^2+2x+1)= -3+8. The first answer 1,2,5

Answer 2

we have

$8x^{2}+16x+3=0$

Step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$8x^{2}+16x=-3$

Step 2

Factor the leading coefficient

$8(x^{2}+2x)=-3$

Step 3

Complete the square. Remember to balance the equation by adding the same constants to each side.

$8(x^{2}+2x+1)=-3+8$

$8(x^{2}+2x+1)=5$

Step 4

Rewrite as perfect squares

$8(x+1)^{2}=5$

$(x+1)^{2}=\frac{5}{8} \\\\(x+1)=(+/-)0.79\\\\x1=0.79-1=-0.21\\\\x2=-0.79-1=-1.79$          

therefore

the answer is

$8(x^{2}+2x)=-3$

$8(x^{2}+2x+1)=-3+8$