Answer:
(x, y, z)
(5,-2,3)
Step-by-step explanation:
try plugging those into the equation.
just to make sure I was correct.
Answer:
yes it is
Step-by-step explanation:
Answer:
20 +/- $6.74
= ( $13.26, $26.74)
The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x1-x2 +/- margin of error
x1-x2 +/- z(√(r1^2/n1 + r2^2/n2)
Given that;
Mean x1 = $200
x2 = $180
Standard deviation r1 = $22.50
r2 = $18.30
Number of samples n1 = 60
n2 = 40
Confidence interval = 90%
z(at 90% confidence) = 1.645
Substituting the values we have;
$200-$180 +/-1.645(√(22.5^2/60 +18.3^2/40)
$20 +/- 6.744449847374
$20 +/- $6.74
= ( $13.26, $26.74)
The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)
Answer:
first choice
Step-by-step explanation:
make 1/3 and 1/2 a common denominator, which is 6.
1x2
- = 2
-
3x 2 6
1 x 3
- = 3
-
2 x 3 6
now u have 2/6, and 3/6
u subtract 2/6 by 3/6 since ur finding a solution to an inequality. remember to do the opposite sign.
2/6-2/6 = 0 (u cancel that out)
3/6 - 2/6 = 1/6
now u have
q>1/6
since there's no 1/6 the first choice is the most accurate
3.4 is the answer (rounded up of course)