$40 is discounted into $32 what is the percent decrease

Mathematics

2 answers:

Sphinxa [80]3 years ago

4 0

About 28.5 percent is the decrease I hope this helps :)

mash [69]3 years ago

3 0

I'm not 100% sure but your answer might be 20%.

I hope this helps. :)

You might be interested in

How many solutions does the following equation have?

RoseWind [281]

Answer:

There will be No solution for the equation $9x - 4 = - 3x + 5 + 12x$ . Option B is correct.

Step-by-step explanation:

We need to determine how many solutions the equation $9x - 4 = - 3x + 5 + 12x$ have.

Solving the equation and finding the solutions

$9x - 4 = - 3x + 5 + 12x$

Combining like terms, Moving 3x and 12x to left side of equality and changing their signs and moving 4 on right side of equation and changing sign.

$9x +3x-12x = 5 + 4$

Simplifying

$12x-12x = 9\\0=9$

Solving the equation we get 0=9 which is false. So, there will be No solution for the equation $9x - 4 = - 3x + 5 + 12x$ . Option B is correct.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20lnx%20%7D%20" id="TexFormula1" title=" \sqrt[4]{ lnx } " alt=" \sqrt[4]

Kamila [148]

Use the power rule for differentiation:

$\dfrac{\text{d}}{\text{d}x} (f(x))^k = k(f(x))^{k-1}f'(x)$

You can use this formula if you remember that a root is just a rational exponential:

$\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}$

So, remembering that the derivative of the logarithm is 1/x, you have

$\dfrac{\text{d}}{\text{d}x} (\ln(x))^{\frac{1}{4}} = \frac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x}$

Which you can rewrite as

$\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}$