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rodikova [14]
3 years ago
8

Pentagons ABCDF and JKLMN below are similar, but not necessarily drawn to scale. Find the values of x and y. A x = 40 mm, y = 15

0 mm B x = 1.6 mm, y = 6 mm C x = 40 mm, y = 6 mm D x = 24 mm, y = 14 mm Find the values of x and y. A x = 40 mm, y = 150 mm B x = 1.6 mm, y = 6 mm C x = 40 mm, y = 6 mm D x = 24 mm, y = 14 mm

Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, but I would show you how to answer a similar question.

We can say that polygons are similar if they have the same shape but not necessary same size. Also their corresponding angles are equal, while their corresponding sides are proportional.

From the image attached, we can see the lengths of the sides, hence we can find the values of x.

\frac{JN}{AE}=\frac{LM}{CD}\\  \\\frac{4.8}{4}=\frac{x}{3}\\  \\1.2=x/3\\\\x=3.6

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The students at a school assembly
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Answer:

292

Step-by-step explanation:

73 students in 1 group

4 groups all together

73 Students times 4 groups = amount of students all together

so 73x4=292

4 0
3 years ago
Can someone show me how to even start with 1 and 2? ​
diamong [38]

All you need to know is that

\displaystyle \lim_{x\to\infty}a^x=\begin{cases} \infty \text{ if } a>1\\1 \text{ if } a=1\\0 \text{ if } 0\leq a

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Arlene is comparing the prices of two truck rental companies. Company A charges $7 per hour and an additional $30 as service cha
max2010maxim [7]
Part A:
Company A:  $7 per hour +$30 service charge =money spent
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Part B:
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7 0
3 years ago
A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban
zalisa [80]

Answer:

<u>4212 : 1573</u> is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be x.

<em>As, sign is similar to banner.</em>

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to x.

\frac{36}{52} =\frac{22}{x}

<em>By cross multiplying we get:</em>

<em />36x=1144<em />

<em>Dividing both sides by 36 we get:</em>

x=31\frac{7}{9} .

<em>Hence, the width of sign is </em>31\frac{7}{9}<em> inches.</em>

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

Area\ of\ banner=36\times 52

Area\ of\ banner=1872\ square\ inches.

Now, area of sign:

Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

1872:\frac{6292}{9}

=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}

<em>On simplifying we get:</em>

=\frac{4212}{1573}

=4212:1573.

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

8 0
3 years ago
9 more than a number is equal to 10
Oliga [24]

Answer:

1

Step-by-step explanation:

9 + 1 is equal to 10. Therefore, the answer is 1.

5 0
3 years ago
Read 2 more answers
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