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3 years ago

6

Milton needs to find the product of two numbers.one of the number is 6. the answer also needs to be 6 how will you solve this pr

oblem?

1 answer:

Goshia [24]3 years ago

7 0

Any number multiplied by one is equal to itself. Therefore, six multiplied by one will be equal to six. As a result, one is the answer.

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Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample.

Zigmanuir [339]

Answer:

$P(E \cup F)=P(E)+P(F)$ .

Step-by-step explanation:

Given the statement

If $P(E)+P(F)=P(E \cup F)+P(E \cap F)$ , then E and F are mutually exclusive events.

If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.

Therefore, the statement is always true as P(E∩F)=0

For mutually exclusive events:

$P(E \cup F)=P(E)+P(F)$ .

3 0

3 years ago

A biology test is worth 100 points and has 36 questions.

Ad libitum [116K]

Answer:

(a) 7 essays and 29 multiple questions

(b) Your friend is incorrect

Step-by-step explanation:

Represent multiple choice with M and essay with E.

So:

$M + E= 36$ --- Number of questions

$2M + 6E = 100$ --- Points

Solving (a): Number of question of each type.

Make E the subject of formula in $M + E= 36$

$E = 36 - M$

Substitute 36 - M for E in $2M + 6E = 100$

$2M + 6(36 - M) = 100$

$2M + 216 - 6M = 100$

Collect Like Terms

$2M - 6M = 100 - 216$

$-4M = - 116$

Divide both sides by -4

$M = \frac{-116}{-4}$

$M = 29$

Substitute 29 for M in $E = 36 - M$

$E = 36 - 29$

$E = 7$

Solving (b): Can the multiple questions worth 4 points each?

It is not possible.

See explanation.

If multiple question worth 4 points each, then

$2M + 6E = 100$ would be:

$4M + xE = 100$

Where x represents the number of points for essay questions.

Substitute 7 for E and 29 for M.

$4 * 29 + x * 7 = 100$

$116 + 7x = 100$

Subtract 116 from both sides

$116-116 + 7x = 100 -116$

$7x = 100-116$

$7x = -16$

Make x the subject

$x = -\frac{16}{7}$

Since the essay question can not have worth negative points.

Then, it is impossible to have the multiple questions worth 4 points

<em>Your friend is incorrect.</em>

6 0

2 years ago

does the following system of equations have a solution if so find it. 2x+y+z= 4 x-y+3z= -2 -x+y+z= -2

saul85 [17]

I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).

Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system

- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.

Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.

Add this result to the first equation. The 2x terms will cancel, leaving you with the system

2y + 2z = -2
y + z = 4

This would be a good time to subst. -1 for z. We then get:

-2y - 2 = -2. Then y must be 0. y = 0.

Now subst. -1 for z and 0 for y in any of the original equations.

For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.

Then a tentative solution is (-3, -1, 0).

It's very important that you ensure that this satisfies all 3 of the originale quations.

5 0

3 years ago

Emily deposits $14,500 each year into a retirement account with a 7% simple interest rate. If she deposits the same amount each

soldier1979 [14.2K]

Hello! I believe she would have 58,000 at the end of her fourth year. Hope this helps. :)

6 0

3 years ago

Read 2 more answers

Ms. Bloom brought 4 packs of treats for Halloween. She gave away 2 1/9 packs of treats to her class and gave away 5/9 packs of t

Eddi Din [679]

Answer: 1 1/3 packs of treats

Step-by-step explanation:

2 1/9 + 5/9 = 2 6/9, which can be simplified to 2 2/3.

We subtract 2 2/3 from 4, giving us 1 1/3

8 0

3 years ago