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4 years ago

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Milton needs to find the product of two numbers.one of the number is 6. the answer also needs to be 6 how will you solve this pr

oblem?

1 answer:

Goshia [24]4 years ago

7 0

Any number multiplied by one is equal to itself. Therefore, six multiplied by one will be equal to six. As a result, one is the answer.

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Valerie is making identical quilts for herself and her sister. For each quilt she buys 5 yards of solid fabric and w yards of pr

Nadusha1986 [10]

Valerie bought 18yrds of fabric. If she used 9yrds of fabric on her quilt, she will use another 9yrds on her sister's. The total is 18yrds.

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3 years ago

A ribbon is cut into n parts. The length of each part increases such that they form a geometric progression. SPM Given the lengt

emmainna [20.7K]

Answer:

Step-by-step explanation:

$Let\ say\ r \ the \common\ ratio:\\a)a_4=r^2*a_2=9*a_2\Longrightarrow\ r=3\ (not\ -3\ since\ parts\ are\ positive)\\\\b)\\\displaystyle \sum_{i=1}^{n} a_i =a_1+a_2+a_3+...+a_n\\\\=a_1+a_1*r+a_1*r^2+a_1*r^3+...+a_1*r^{n-1}\\\\=a_1*(1+r+r^2+...+r^{n-1})\\\\=a_1*\dfrac{r^n-1}{r-1} \\\\147620=5*\frac{(3^n-1)}{3-1} \\\\3^n-1=\frac{2*147620}{5} \\\\3^n=59049 \\\\n*ln(3)=ln(59049)\\\\n=\dfrac{ln(59049)}{ln(3)} \\\\n=10\\\\a_n=5*3^{10-1}=5*19683=98415(cm)$

5 0

3 years ago

Ellie runs 5/6 mile in 10 minutes.what is ellie's speed in miles per minute?

olganol [36]

Answer:

1/12 miles/minute

Step-by-step explanation:

To figure out how fast ellie runs in 1 minute, we can set up this equation:

5/6 = 10x (x being the speed per minute)

We can divide both sides by 10

5/60 = x

Then simplify the fraction to get:

1/12 = x

4 0

3 years ago

How do you solve 5-4x<95

mario62 [17]

$5 - 4x < 95 \\ - 4x < 95 - 5 \\ - 4x = 90 \\ x = - \frac{90}{4} \\ \boxed{ x = - \frac{45}{2} }$

8 0

3 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

4 years ago