Option 3:
m∠ABC = 66°
Solution:
Given 
and ABH is a transversal line.
m∠FAB = 48° and m∠ECB = 18°
m∠ECB = m∠HCB = 18°
<u>Property of parallel lines:
</u>
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠FAB = m∠BHC
48° = m∠BHC
m∠BHC = 48°
<u>Exterior angle of a triangle theorem:
</u>
<em>An exterior angle of a triangle is equal to the sum of the opposite interior angles.</em>
m∠ABC = m∠BHC + m∠HCB
m∠ABC = 48° + 18°
m∠ABC = 66°
Option 3 is the correct answer.
Answer:
At 43.2°.
Step-by-step explanation:
To find the angle we need to use the following equation:
Where:
d: is the separation of the grating
m: is the order of the maximum
λ: is the wavelength
θ: is the angle
At the first-order maximum (m=1) at 20.0 degrees we have:
Now, to produce a second-order maximum (m=2) the angle must be:
Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.
I hope it helps you!
59 degrees!
because you set up your problem: 3c+2+2c-7=90
then combine all like terms: 5c-5=90
Add 5 to both sides: 5c=95
then divide both sides by 5: c=19
Plug in your answer: 3(19)+2=59
