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Phantasy [73]
3 years ago
15

The Shavertown School picnic served 7 gallons of lemonade.

Mathematics
2 answers:
denpristay [2]3 years ago
7 0
56 pints of lemonade were served.
guapka [62]3 years ago
3 0

Answer:

56

Step-by-step explanation:

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The center on a target has a diameter of 5 inches. The whole target has a diameter of 25 inches. Complete the explanation for wh
kicyunya [14]

Answer:

The center is \frac{1}{25} of the whole target.

Step-by-step explanation:

Given:

Diameter of the center = 5 inches

Diameter of the whole target = 25 inches

We need to find the part of the center to the whole target.

Solution,

Firstly we will find out the areas of center and whole target.

For center;

Diameter = 5 in

Radius of circle is equal to half of the diameter.

radius = \frac{diameter}{2}=\frac{5}{2}=2.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = \pi \times{2.5}^2

For whole target;

Diameter = 25 in

Radius of circle is equal to half of the diameter.

radius = \frac{diameter}{2}=\frac{25}{2}=12.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = \pi \times12.5^2

Now to find the part of the center to the whole target we will divide Area of center with Area of the target.

framing in equation form we get;

the part of the center to the whole target = \frac{\pi \times2.5^2}{\pi \times12.5^2}= \frac{6.25}{156.25} = \frac{1}{25}

Hence the center is \frac{1}{25} of the whole target.

6 0
3 years ago
PLEASE ANSWER AND EXPLAIN | 98 POINTS
DIA [1.3K]

Answer:

Step-by-step explanation:

R-value can range from -1 to 1 with correlation being strongest at -1 and 1 and weakest at 0.

So the answer is D. -0.9.

3 0
4 years ago
Read 2 more answers
Please answer the picture
Fiesta28 [93]
12x^2 = 4/3
x^2 = 1/9
x= +/- 1/3 
6 0
3 years ago
Simplify the expressions by combining like terms<br><br> 4r + 9r - 11r + 7r
konstantin123 [22]
9r
Explanation:
4r + 9r = 13r
13r-11r = 2r
2r + 7r = 9r
4 0
3 years ago
Read 2 more answers
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
3 years ago
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