All categories

3 years ago

Find each product. (5-x2+2)(-3) PLEASE HELP!!! ASAP!!!

Mathematics

1 answer:

Bumek [7]3 years ago

3 0

Answer:

$3x^2 - 21$ (did you mean for the equation to be $(5 - x^2 + 2) \cdot -3$ ?)

Step-by-step explanation:

Multiplying -3 by each term:

$-3 \cdot 5 = -15$

$-x^2 \cdot -3 = 3x^2$

$-3 \cdot 2 = -6$

$-15-6 = -21$

So the equation comes out to $3x^2 - 21$ .

Hope this helped!

You might be interested in

HELP ASAP What is the value of x? O x = 55° O x = 60° O x = 70° O x = 110°

valina [46]

Answer:

the answer is the answer the answer is x=55 degrees because the angle sum for a triangle is 180 degrees and because we are told angle A and angle C are congruent that means you can simply take 180 - 70 to get 110 and i simply divided that by 2 and got 55 degrees

Step-by-step explanation:

5 0

2 years ago

A truck is rented at $40 per day plus a charge per mile of use. The truck traveled 15 miles in one day, and the total charge was

lesantik [10]

15x+40=115
15x+40-40=115-40
15x=75
15/15 x=75/15
x= 5

6 0

3 years ago

Write an equation in slope-intercept form of the line that passes through (-1,-3) and is parallel to the graph of y=4.

strojnjashka [21]

Use the point slope equation: y - y1 = m(x - x1)

(-1, -3); m = 4
Plug these numbers in.

y - (-3) = 4(x - -1)
y + 3 = 4x + 4
y = 4x + 1

3 0

2 years ago

Read 2 more answers

PLease help

Kipish [7]

It is longing because it is the definition of yearning

7 0

2 years ago

Read 2 more answers

What 2 numbers add to get 2 and multiply to 4

rusak2 [61]

Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x= $\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a}$ so

1x^2-2x+4=0
a=1
b=-2
c=4
x= $\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}$
x= $\frac{ 2+/-\sqrt{4-16} }{2}$
x= $\frac{ 2+/-\sqrt{-12} }{2}$
we have $\sqrt{-12}$ and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x= $\frac{ 2+/-2\sqrt{-3} }{2}$
i= $\sqrt{-1}$
x= $\frac{ 2+/-2i\sqrt{3} }{2}$
x= $1+/-i\sqrt{3}$
x= $1-i\sqrt{3}$ or x= $1+i\sqrt{3}$ (those are the 2 numbers)

6 0

3 years ago