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2 years ago

HELPP ME PLEASE I NEED TO FINISH BEFORE FLVS LOGS ME OUT HELPPPPP

Mathematics

1 answer:

Mice21 [21]2 years ago

5 0

Answer:

part a is about 55%

part b I'm not too sure about, but it might be 60%

part c I have no idea, sorry

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Verify the identity. <br> Please show your work.

m_a_m_a [10]

Step-by-step explanation:

To prove :

( 1 - sin x ) ( 1 + sin x ) = sec² x

LHS : -

( 1 - sin x ) ( 1 + sin x )

Formula / Identity : -

( a - b ) ( a + b ) = a² - b²

Here,

a = 1

b = sin x

( 1 - sin x ) ( 1 + sin x )

= 1 - sin² x

Identify : -

sin² θ + cos² θ = 1

cos² θ = 1 - sin² θ

Similarly,

1 - sin² x

= cos² x

= RHS

Hence verified.

5 0

2 years ago

Estimate 1.9 x 4.4

Lelechka [254]

Answer:

Step-by-step explanation:

1.9 about 2, and 4.4 is about 4.

2x4=8

So it is safe to say between 4 and 10.

3 0

2 years ago

PLEASE HELP !! I'LL GIVE YOU BRAINLIEST !!

Marizza181 [45]

Sorry but, there’s nothing attached so I can not help you.

3 0

2 years ago

Read 2 more answers

A plumbing contractor bid the rough-in work for a new three-story office building based an estimate of 850 hours of a journey

Elodia [21]

There is 179 hours left.

-Hiadamcom

6 0

2 years ago

the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2

Ksivusya [100]

Answer:

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ .

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is $\frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1$ .

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by $b^{2} = a^{2}(e^{2} - 1) = 4[(\frac{5}{2} )^{2} -1] = 21$ {Since $e = \frac{5}{2}$ given}

Therefore, the equation of the given hyperbola will be

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ . (Answer)

6 0

2 years ago