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4 years ago

Evaluate x3 - 3y when x = -3 and y = 4.

Mathematics

2 answers:

miskamm [114]4 years ago

8 0

I think the answer is
-9-12=-21

Svetllana [295]4 years ago

4 0

Answer:

Step-by-step explanation:

-3^3-3*4

-27-3*4

-27-12

-37

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12. Lin has $212 in her savings account. Her goal is to have $800 in the account in 21 weeks. How much does

uranmaximum [27]

Answer: Lin must save at least $28 a week

Step-by-step explanation:

I got my answer by subtracting the already earned $212 from the neccessary $800 and that got me $588. Then divided the $588 by the 21 weeks from her goal to get my answer of at leaast $28 a week.

3 0

3 years ago

Find the values of the variables for the parallelogram <br> measure angle 1 = 4y - 10

matrenka [14]

The value of x and z are 15 and 4.5 respectively

<h3>Parallelogram and triangles</h3>

The triangles in the parallelogram are isosceles. This shows that the base angles are equal

From the given parallelogram, the following are true

3x = 45

x = 45/3

x = 15

Similarly;

10z = 45

z = 45/10

z = 4.5

Hence the value of x and z are 15 and 4.5 respectively

Learn more on parallelogram here: brainly.com/question/3050890

6 0

3 years ago

Please unswer this!!

quester [9]

Answer:

176 cm

Step-by-step explanation:

You can use the Pythagorean theorem to find the hypotenuses of each triangle by sibstituting the given lengths of each leg.

8 0

3 years ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$