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pishuonlain [190]
3 years ago
9

The 3 × 3 matrix P satisfies the matrix equation P^2 = P.

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0

Answer:  The answers are given below.

Step-by-step explanation:  Given that a  3 × 3 matrix P satisfies the matrix equation P² = P.

We are to

(a) find the possibilities for the determinant of P.

(b) explain the reason behind there are no other possibilities.

(c) give an example of P, for each possible determinant.

(a) According to the given information, we have

P^2=P\\\\\Rightarrow P^2-P=0\\\\\Rightarrow P(P-I)=0\\\\\Rightarrow P=0,~~~P=I.

So, P can be either a zero matrix of order 3 or an identity matrix of order 3.

If P = 0, then det(P) = 0     and     if P = I, then det(P) = 1.

Therefore the possible determinants of P are 0 and 1.

(b) There can be any other determinant other than 0 and 1, because if so, then the given equation P² = P will not be satisfied.

(c) If |P| = 0, then the matrix P can be can be of the form as follows:

P=\left[\begin{array}{ccc}0&0&0\\0&0&0\\0&0&0\end{array}\right] .

If |P| = 1, the the matrix P can be of the form as follows :

P=\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] .

Thus, all the parts are answered.

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Just wash all of it geez

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3 years ago
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Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
Naddik [55]

Given the parameters in the diagrams, we have;

4. ∆ABC ≈ ∆DEF by ASA

5. UW ≈ XZ by CPCTC

6. QR ≈ TR by CPCTC

<h3>How can the relationship between the triangles be proven?</h3>

4. The given parameters are;

<B = <E = 90°

AB = DE Definition of congruency

<A = <D Definition of congruency

Therefore;

  • ∆ABC ≈ ∆DEF by Angle-Side-Angle, ASA, congruency postulate

5. Given;

XY is perpendicular to WZ

UV is perpendicular to WZ

VW = YZ

<Z = <W

Therefore;

∆UVW ≈ ∆XYZ by Angle-Side-Angle, ASA, congruency postulate

Which gives;

  • UW is congruent to XZ, UW ≈ XZ, by Corresponding Parts of Congruent Triangles are Congruent, CPCTC

6. Given;

PQ is perpendicular to QT

ST is perpendicular to QT

PQ ≈ ST

From the diagram, we have;

<SRR ≈ <PRQ by vertical angles theorem;

Therefore;

∆QRP ≈ ∆TRS by Side-Angle-Angle, SAA, congruency postulate

Which gives;

  • QR ≈ TR by Corresponding Parts of Congruent Triangles are Congruent, CPCTC

Learn more about congruency postulates here:

brainly.com/question/26080113

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5 0
1 year ago
Please help, I’ll mark your answer as brainliest.
Brrunno [24]

Answers:

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\\\(f \circ g)(2) = \sqrt{401}\\\\

========================================================

Work shown for part 1

f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\

----------------------------------

Work shown for part 2

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\

6 0
2 years ago
How do I solve this question?
Oduvanchick [21]

9514 1404 393

Answer:

  no, y does not vary directly with x

Step-by-step explanation:

If there is direct variation, the constant of variation can be found as ...

  k = y/x

Here, those ratios are ...

  y/x = 6/3 = 2

  y/x = 18/6 = 3

  y/x = 24/8 = 3

The ratio of y to x is NOT A CONSTANT, so <em>there is no direct variation.</em>

4 0
3 years ago
Two lines, E and F, are represented by the equations given below.
shusha [124]
Although you have not included the statements about the solution to the set of the given equations, I can explain you what happen with that system.

You can arrive to the same conclusion by any method of solution of systems that you like.

The quickest in this case, is to multiply the equation of the lIne F by 5.

That leads to: 5 (x + y) = 5(8)

⇒ 5x + 5y = 40.

Now you can realize that the two representations (equations) correspond to the same line.

That means that there are infinite solutions, this is infinity values of x and y meet both equations.

If you graph line E and line F they overlap in the entire domain, so the graphing method also tells you that you cannot find one solution but infinite soluttions.

6 0
3 years ago
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