We have two unknowns and two equations so we can solve this question.
The two unknowns are C (speed of current) and B (speed of boat)
Our boat traveled 20 miles in 55 hours going upstream which means it traveled .36 miles in 1 hour; in other words .36mph . Our boat traveled 50 miles in 55 hours going downstream; in other words .909mph .
We can assume that because the boat managed to cover distance in the direction it was headed upstream it must have been going faster than the current so it moved at the speed of the boat minus the speed of the current and when it was going downstream it moved at the speed of the boat plus the speed of the current.
This gives us;
.36mph = B - C
.909mph= B + C
We solve for this system of equations and it simplifies to 1.27mph=2B
and B= .636mph
Plug this into one of the equations and we get that C= .2727mph
This means that the boat moved at .363mph and the current moved at .2727mph.
Answer:
Step-by-step explanation:
Let 
and 
.
The slope of AC can be found using
Substitute the variables to get;
Answer:
Step-by-step explanation:
i² = -1
i⁵ = i² * i² * i
= (-1) * (-1) * i
i⁵ = i
i²⁵ = i ⁵ˣ⁵ = (i⁵)⁵
= (i)⁵
= i
10 times as much as .09? do you mean 10 times .09?
If so, then .9
The solution is (3,1)
The solution is where the 2 lines intersect and you can see that the point is across 3 up 1
