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3 years ago

2x^3y + 18xy - 10x^2y - 90y Part A: Rewrite the expression so that the GCF is factored completely. (3 points)

Mathematics

1 answer:

Verizon [17]3 years ago

4 0

2y(x3+9x-10x2-45) not much to be taken as a common factor

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Im sorry for so many questions but i need help badly.

vlada-n [284]

The ratio of the circumference to the diameter is defined as pi
pi=circumference/diameter
that is how they got pi
in this question it woul be 15.7/5 which would be 3.14,

c=2pir
a=pir^2

c=2pir=16pi
divide both sides by 2pi
r=8

a=pir^2
a=pi8^2
a=pi64
a=64pi in²

5 0

2 years ago

I need to know what the volume of the cone in cubic inches please

ivolga24 [154]

Answer:

V = 118 in³

Step-by-step explanation:

The volume of a cone of radius r and height h is V = (1/3)(π)(r^2)(h).

In this case, the volume is V = (1/3)π(3 in)^2·(6 in), or π(18 in³)

Using 3.14 as the approximate value of π, we get V = 118 in³

6 0

2 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago

Justify your reasoning

love history [14]

Answer:

Yes

Step-by-step explanation:

You can conclude that ΔGHI is congruent to ΔKJI, because you can see/interpret that there all the angles are congruent with one another, like with vertical angles (∠GIH and ∠KIJ) and alternate interior angles (∠H and ∠J, ∠G and ∠K).

We also know that we have two congruent sides, since it provides the information that line GK bisects line HJ, meaning that they have been split evenly (they have been split, with even/same lengths).

So now we have three congruent angles, and two congruent sides. This is enough to prove that ΔGHI is congruent to ΔKJI,

7 0

2 years ago

Heather measured a swimming pool and made a scale drawing. In real life, the pool is 45 meters long. It is 65 millimeters long i

oksano4ka [1.4K]

Greetings!

"Heather measured a swimming pool and made a scale drawing. In real life, the pool is 45 meters long. It is 65 millimeters long in the drawing. What scale did Heather use for the drawing?"...

65mm=45m
Reduce to Simpliest Form.
65/5=45/5
13mm=9m

As a Representative Fraction (scale), it would look like: (in regards to mm)
13:9000

Hope this helps.
-Benjamin

4 0

3 years ago