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jonny [76]
3 years ago
9

Make y the subject y-aw=2w-1

Mathematics
1 answer:
Fudgin [204]3 years ago
8 0

Answer:

y = 2w - 1 + aw

Step-by-step explanation:

Given

y - aw = 2w - 1 ( isolate y by adding aw to both sides )

y = aw - 1 + aw

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A box contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that
Igoryamba

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

\frac{1}{5}

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

P(A\cap B)=P(A).P(B)

Now, According to question , we can get that

P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}

So,

P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}

So, by using the conditional probability , which state that

P(B\mid A)=\frac{P(A\cap B)}{P(A)}

P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

\frac{1}{5}


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