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Setler [38]
2 years ago
14

Dairy farmers are aware there is often a linear relationship between the age, in years, of a dairy cow and the amount of milk pr

oduced in gallons per week The least squares regression line
produced from a random sample is Milk = 40.8 – 1.1 (Age). Based on the model, what is the difference in predicted amounts of milk produced between a cow of 5 years and a cow of 10 years?

A cow of 5 years is predicted to produce 5.5 fewer gallons per week

B A cow of 5 years is predicted to produce 5.5 more gallons per week

c) A cow of 5 years is predicted to produce 1.1 fewer gallons per week

D) A cow of 5 years is predicted to produce 1.1 more gallons per week

A cow of 5 years and a cow of 10 years are both predicted to produce 40.8 gallons per week
Mathematics
1 answer:
Jobisdone [24]2 years ago
6 0

Answer:

B. A cow of 5 years is predicted to produce 5.5 more gallons per week.

Step-by-step explanation:

Let M(a) = 40.8-1.1\cdot a, where a is the age of the dairy cow, measured in years, and M(a) is the predicted milk production, measured in gallons per week.

Besides, we consider a_{1} and a_{2}, such that a_{1}\ne a_{2}, we define the difference between predicted milk productions (\Delta M) below:

\Delta M = -1.1\cdot (a_{2}-a_{1}) (1)

If we know that a_{1} = 5\,yr and a_{2} = 10\,yr, then the difference between predicted milk productions is:

\Delta M = -1.1\cdot (10-5)

\Delta M = -5.5\,\frac{gal}{week}

That is, a cow of 5 years is predicted to produce 5.5 more gallons per week than a cow of 10 years. Hence, the right answer is B.

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Pls Help!
mr Goodwill [35]

Answer:

34 Braids

Step-by-step explanation:

.85 per braid means 1 is 85 cents, 2 is $1.70 and so on.  So normally you would just divide the total amount of money, so for instance if you had $2.55 you would be able to afford 3 braids, since 3 braids cost $2.55.  in fact $2.56, $2.57 aaaaaaaaaaall the way up to $3.39 would be 3 braids, then $3.40 would be 4 braids.

Here though you first pay 3 dollars.  so you need 3 first, then an extra 85 cents to get 1 braid.  2 braids is 3 dollars plus 1.70, 3 braids is 3 + 2.55 4 braids is 3 + 3.40 and so on.

So what you want to do is first take away that 3 dollars you need before the braids, then divide by .85.  for instance $6.40 would get you 4 braids as I showed bcause 3 + 3.40 = 6.40.  now 6.40 - 3 = 3.40 then 3.40 divided by .85 = 4

The problem says we start with$32, so lets do those steps.  first 32 - 3 = 29.  then 29 divided by .85 = 34.11.  well it's not  whole number so lets try something.  34 braids would be 3 + .85*34 = 31.90 and 35 braids would be 32.75  So 31.90, 31.91 aaaaaaaaall the way up to 32.74 would be 34 braids then 32.75 would be 35 braids.  well, $32 is in that in between space, so it is 34 braids.

When I did 32 - 3 = 29.  then 29 divided by .85 = 34.11 that 34.11 does actually tell us we wouldn't get to 35, I just wanted to make it very clear.  so the answer is 34 braids.

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V o = 15 m/s,  a = 2 m/s²,  t = 15 s
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