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mina [271]
3 years ago
10

What is the solution to the division problem below? (You can use long division or synthetic division)

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
P(x) = 2x^2 - 4x^2 - 9
g(x) = x - 3
q(x) = 2x^2 + 2x + 6
r(x) = 9
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A railroad crew can lay 6 miles of track each day. They need ti lay 174 miles of track. The length, L (in miles), that is left t
Alex17521 [72]
X + y = 13
- x + y = 3
6 0
3 years ago
6 = 2 (y + 2)<br><br> find X <br> please
Elena-2011 [213]

Answer: y = 1

there no x, i think you meant y?

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6=2(y+2)

6=(2)(y)+(2)(2)(Distribute)

6=2y+4

Step 2: Flip the equation.

2y+4=6

Step 3: Subtract 4 from both sides.

2y+4−4=6−4

2y=2

Step 4: Divide both sides by 2.

2y over 2 = 2 over 2

6 0
3 years ago
Please give Examples for real life examples for expressing very small number sin standard form.
Digiron [165]
Scientific notation is a system for expressing very large or very small numbers in a compact manner. It uses the idea that such numbers can be rewritten as a simple number multiplied by 10 raised to a certain exponent, or power.
3 0
3 years ago
If I have 24 jolly ranchers and 64 starbursts what is the largest amount of bags I can fill? How many starbursts will be I’m eac
Rus_ich [418]

Answer:

Largest amount of bags that can be filled: 11

Starbursts in each bag: 3

Step-by-step explanation:

Find the greastest common factor between these two (which is 8) and divide the sum of the jolly ranchers and starbursts-which will be 88-by the greatest common factor. This will leave you with 11 bags that can be filled with 8 candies. To find the starbursts, divide 24 by 8 (3.)

5 0
3 years ago
show that the sum of the x- and y- intercepts of any tangent line to the curve sqrt(x) sqrt(y) = sqrt(c) is equal to c.
expeople1 [14]
The answer is <span>√x + √y = √c </span>
<span>=> 1/(2√x) + 1/(2√y) dy/dx = 0 </span>
<span>=> dy/dx = - √y/√x </span>

<span>Let (x', y') be any point on the curve </span>
<span>=> equation of the tangent at that point is </span>
<span>y - y' = - (√y'/√x') (x - x') </span>

<span>x-intercept of this tangent is obtained by plugging y = 0 </span>
<span>=> 0 - y' = - (√y'/√x') (x - x') </span>
<span>=> x = √(x'y') + x' </span>

<span>y-intercept of the tangent is obtained by plugging x = 0 </span>
<span>=> y - y' = - (√y'/√x') (0 - x') </span>
<span>=> y = y' + √(x'y') </span>

<span>Sum of the x and y intercepts </span>
<span>= √(x'y') + x' + y' + √(x'y') </span>
<span>= (√x' + √y')^2 </span>
<span>= (√c)^2 (because (x', y') is on the curve => √x' + √y' = √c) </span>
<span>= c.  hope this helps :D</span>
5 0
3 years ago
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