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ivolga24 [154]
3 years ago
7

What is the answer or how do I solve this

Mathematics
2 answers:
mojhsa [17]3 years ago
6 0

Answer:

x=21

<EAF=52°

<EAL=104°

Step-by-step explanation:

Since it has a bisector, the two angles are equal.

2x+10=3x-11

10+11=3x-21

21=x

<EAF=2x+10 = 2(21)+10 = 42+10 = 52°

<EAL=52*2=104°

Irina-Kira [14]3 years ago
5 0
Can you make your question more clear
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What is the LCM of 12,30 and 42
Hoochie [10]

Answer:

420

Step-by-step explanation:

We can find the prime factors of each of the numbers first before finding their LCM.

12: <em>2</em> × 2 × <u>3</u>

30: <em>2</em> × <u>3</u> × 5

42: <em>2</em> × <u>3</u> × 7

To find the LCM, we need to see if they are any common prime factors between all three numbers. The common prime factors are <em>2</em> and <u>3</u>. Then, we multiply 2 and 3 with the remaining outstanding factors, which are 2, 5, and 7.

LCM: <em>2</em> × 2 × <u>3</u> × 5 × 7 = 420

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3 years ago
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3217.00

Step-by-step explanation:

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93.64m to metres and centimetres
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single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec
givi [52]

Answer:

\frac{1}{4}

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

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A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

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Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = \frac{3}{6} = \frac{1}{2}

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

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The probability of rolling a number greater than 3 =  \frac{3}{6} = \frac{1}{2}

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}

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