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alexandr1967 [171]
3 years ago
7

Approximately how many times greater is 6 x 10^-5 than 5 x 10^-9

Mathematics
1 answer:
8_murik_8 [283]3 years ago
8 0

Answer: 6 \times 10^{-5} is 1.2 \times 10^4. times greater than 5 \times 10^{-9}.


Step-by-step explanation:

We are given two numbers.

First number  : 6 \times 10^{-5}.

Second number : 5 \times 10^{-9}.

In order to find how many times   6 \times 10^{-5} is greater than 5 \times 10^{-9}, we need to divide first number by second number.

Therefore,

6 \times 10^{-5} ÷ 5 \times 10^{-9}

or \frac{6 \times 10^{-5}}{5 \times 10^{-9}}

First we would divide 6 by 5.

On dividing 6 by 5, we get 1.2.

Now, we would divide 10^-5 by 10^-9.

In order to divide them, we can apply quotient rule of exponents \frac{a^m}{a^n} =a^{m-n}.

We get

\frac{10^{-5}}{10^{-9}}  = 10^{-5-(-9)} = 10^{-5+9} = 10^4.

Therefore,

\frac{6 \times 10^{-5}}{5 \times 10^{-9}} = 1.2 \times 10^4.

So, we could say finally 6 \times 10^{-5} is 1.2 \times 10^4. times greater than 5 \times 10^{-9}.

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mars1129 [50]

Answer:

The equation of the circle is (x + 4)^2 + (y - 10)^2 = 64, third option is correct.

Step-by-step explanation:

Equation of a circle:

The equation of a circle with center (x_0,y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

Center at (-4, 10)

This means that x_0 = -4, y_0 = 10.

Radius of 8:

This means that r = 8. So

(x - x_0)^2 + (y - y_0)^2 = r^2

(x - (-4))^2 + (y - 10)^2 = 8^2

(x + 4)^2 + (y - 10)^2 = 64

The equation of the circle is (x + 4)^2 + (y - 10)^2 = 64, third option is correct.

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3 years ago
wai and kuri were digging in the sand at the beach. wai dug a hole that was 15 inches below the surface and kuri dug a hole that
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Step-by-step explanation:

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7 0
4 years ago
Beatrice built about 1/3 of a sandcastle. Linda built 4/7 of the same castle. What fraction of the sandcastle did they build tog
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Answer    

Find out the what fraction of the sandcastle did they build together .

To prove

Let us assume that the fraction of the sandcastle  they build together be x .

As given

Beatrice\ built\ about\ \frac{1}{3}\ of\ a\ sandcastle.

Linda\ built\ \frac{4}{7}\ of\ the\ same\ castle.

Than the equation becomes

x = \frac{1}{3} +\frac{4}{7}

L.C .M of (3,7) = 21

solving

x = \frac{7 + 3\times4}{21}

x = \frac{19}{21}

Therefore the fraction of the sandcastle did they build together be

x = \frac{19}{21}

Hence proved



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