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Likurg_2 [28]
3 years ago
12

In the circle, m BC = 94°. The diagram is not drawn to scale.

Mathematics
1 answer:
Vlada [557]3 years ago
5 0

this is the diagram i need help too please

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Sharon and Jacob started at the same place. Jacob walked 3 m north and then 4 m west. Sharon walked 5 m south and 12 m east. How
Ilya [14]

Consider the coordinate plane:

1. The origin is the point where Sharon and Jacob started - (0,0).

2. North - positive y-direction, south - negetive y-direction.

3. East - positive x-direction, west - negative x-direction.

Then,

  • if Jacob walked 3 m north and then 4 m west, the point where he is now has coordinates (-4,3);
  • if Sharon walked 5 m south and 12 m east, the point where she is now has coordinates (12,-5).

The distance between two points with coordinates (x_1,y_1) and (x_2,y_2) can be calculated using formula

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

Therefore, the distance between  Jacob and Sharon is

D=\sqrt{(12-(-4))^2+(-5-3)^2}=\sqrt{16^2+8^2}=\sqrt{256+64}=\sqrt{320}=8\sqrt{5}\approx 11.18\ m.

7 0
4 years ago
The longest side of the right triangle is 2 feet more than the middle side and the middle side is 1 foot less than twice the sho
Ket [755]
A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
3 0
3 years ago
Classify the limaçon represented by the equation r=(1/2)-(1/2)sin(theta)
babunello [35]
We know that

Limacons are in the form
r=a(+-)b*sin (theta)  or r=a(+-)b*cos (theta)

in this problem
r=a(+-)b*sin (theta)
so
is symmetric to y axis
a=1/2
b=1/2
a/b=1---------> Cardioid (hearth shaped)

see the attached figure

the answer is the option
<span>A. Cardioid </span>

4 0
3 years ago
5. The table below represents fees for a parkirls lot. Graph the
Vladimir [108]

Answer:

15$

Step-by-step explanation:

5 0
3 years ago
What is the equation of the circle that has a center at (-3, 1) and a radius of 5? A) (x + 3)2 + (y - 1)2 = 5 B) (x - 3)2 + (y +
Gnoma [55]

Answer:

C

Step-by-step explanation:

The vertex form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center of the circle and r is the radius. This means that for the circle with center (-3,1) and radius 5 substitute into the vertex form these values. Substitute h = -3, k= 1, and r = 5. The equation becomes (x--3)^2 + (y-1)^2 = 5^2. This simplifies to (x+3)^2 + (y-1)^2 = 25. The solution is C.

7 0
3 years ago
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