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3 years ago

Use Long Division to find the answer. Please show all steps!

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

5 0

Answer:

The answer to your question is 2x² + 3x + Remainder (17x - 7)/ ( 2x⁴ + 3x³ - 4x² + 5x - 7)

Step-by-step explanation:

2x² + 3x

x² - 4 2x⁴ + 3x³ - 4x² + 5x - 7

-2x⁴ + 4x²

0 + 3x³ + 0 + 5x

- 3x³ +12x

0 +17x - 7

Quotient = 2x² + 3x

Remainder = 17x - 7

Solution = 2x² + 3x + (17x - 7)/ ( 2x⁴ + 3x³ - 4x² + 5x - 7)

Process

1.- Divide the first term of the divident by the first term of the divisor and place the result above the first term of the divident.

2.- Multiply the result of the division (2x²) by the first term of the divisor and change the sign of the result.

3.- Multiply the result (2x²) by the second term of the divisor and place the result below the like term.

4.- Add the results.

5.- Continue with this process until the remainder be lower than the divisor.

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3 years ago

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3 years ago

A swing forward 50 degree and back 95 degree. How many degree forward must the swing go to return in starting position

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2 years ago

What is the volume of the following triangular prism?<br> 60 cm3<br> 12 cm3<br> 3.75 cm3<br> 6 cm3

DochEvi [55]

By definition, the prism volume is given by:
$V = Ab * L
$ Where,
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L: long
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2 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago