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I am Lyosha [343]

3 years ago

9

Somebodyy help running out of time!!!!

1 answer:

Oliga [24]3 years ago

8 0

1. The answer is d
2. The answer is a
3. The answer is a. The slope of a constant function is always 0.

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how much cardboard would you need to construct a rectangular prism shaped box measuring 15 inches by 13 inches by 7 inches

givi [52]

We know that

[surface area]=2*[area of the base]+[perimeter of the base]*height

area of the base=15*13----> 195 in²

perimeter of the base=2*[15+13]----> 56 in
height=7 in
so
[surface area]=2*[195]+[56]*7-----> 782 in²

the answer is
782 in²

6 0

3 years ago

Natalie is in the business of manufacturing phones. She pays a cost of $50 per

Trava [24]

Answer:

C = 50p +900

Step-by-step explanation:

Table: (phones, cost) = (0, 900), (1, 950), (2, 1000).

Equation: C = 900 +50p

__

The fixed cost (900) is the "y-intercept" of the equation in slope-intercept form. The cost per phone (50) is the "rate of change" or slope.

5 0

3 years ago

1. Garbage Production. Based on a sample of 62 households, the mean weight of discarded plastic is 1.93 pounds and the standard

Contact [7]

Answer:

The answer is below

Step-by-step explanation:

Given that:

Mean (μ) = 1.93, standard deviation (σ) = 1.08 pounds, sample (n) = 62.

the mean weight of discarded plastic for all household is given by:

$\mu_x=\mu = 1.93\ pounds$

The standard deviation of discarded plastic for all household is given by:

$\sigma_x=\frac{\sigma}{\sqrt{n} } =\frac{1.08}{\sqrt{62} }=0.137\ pounds$

The confidence (c) = 90% = 0.9

α = 1 - c = 1 - 0.9 = 0.1

α/2= 0.1/2 = 0.05

The z score of 0.05 corresponds to the z score of 0.45 (0.5 - 0.05) which is 1.645. i.e. $z_\frac{\alpha}{2}=z_{0.05}=1.645$

The margin of error (E) = $z_{0.05}\frac{\sigma}{\sqrt{n} }=1.645*\frac{1.03}{\sqrt{62} }= 0.2256$

The confidence interval = $\mu \pm E=1.93 \pm 0.2256=(1.7044,2.1556)$

We are 90% confidence that the value is between 1,7044 and 2.1556

6 0

4 years ago

ABCD = EFGH find EF <br> ab=5 dc=4 fg=1

iVinArrow [24]

AB=EF, so EF=5.

5 is your answer.

7 0

3 years ago

If a fair die is tossed, find the probability that the uppermost face displays a(n):

vladimir2022 [97]

if a fair dice is tossed the probability is (T, H) (H, T) ( T, T) (H, H)

5 0

3 years ago