1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
exis [7]
4 years ago
15

Write y=1/6x+4 In standard Form using Integers?

Mathematics
2 answers:
steposvetlana [31]4 years ago
7 0

-x+6y=4 is the answer

nexus9112 [7]4 years ago
4 0
<span>y=1/6x +4 is already in standard form, but the coefficient 1/6 is not an integer. An integer number is not a fraction number or rational number, so in order we have a standard form with integers coefficients only, multiply each member of the equation by 6. that is 6y =x +24, and 4y = x + 16 is the final answerHope this helps. Let me know if you need additional help!</span>
You might be interested in
I KINDA NEED HELP WITH THIS ILL GIVE BRAINLIST WHOEVER HAS THE CORRECT ANSWER! THANKS
Drupady [299]

Answer: 48

Step-by-step explanation: YOU MULTIPLY 6 AND 8.

6 0
3 years ago
Read 2 more answers
3√x -2/x^2<br><br>please show step by step of differentiation before combining the terms. ​
EastWind [94]

Answer:

Step-by-step explanation:

Before we differentiate, let us assign a variable to the function. Let y be equal to the function i.e let y = 3√x -2/x²

In differentiation if y = ax^{n}, then \frac{dy}{dx} = nax^{n-1} where n is a constant and dy/dx means we are differentiating the function y with respect to x.

Applying the formula o the question given;

y= 3\sqrt{x}  -2/x^2\\y = 3{x}^\frac{1}{2}  - 2x^{-2} \\\\

On differentiating the resulting function;

\frac{dy}{dx} = \frac{1}{2}*3x^{\frac{1}{2}-1 }   - (-2)x^{-2-1} \\\\\frac{dy}{dx} = \frac{1}{2}*3x^{-\frac{1}{2}} + 2x^{-3}\\ \\\frac{dy}{dx} = \frac{1}{2}*{\frac{3}{x^{\frac{1}{2} } }} + \frac{2}{x^{3} } \\\\\frac{dy}{dx} = {\frac{3}{2x^{\frac{1}{2} } }} + \frac{2}{x^{3} }\\\\\frac{dy}{dx} = {\frac{3}{2\sqrt{x}  }} + \frac{2}{x^{3} }

To combine the terms, we will add up by finding their LCM.

\frac{dy}{dx} = {\frac{3}{2\sqrt{x}  }} + \frac{2}{x^{3} }\\\frac{dy}{dx}  = \frac{3x^3+4\sqrt{x} }{2x^{3} \sqrt{x}}

3 0
4 years ago
What is the value of x in the equation 8 + x = 3?<br><br> A. −5<br> B. 5<br> C. 11<br> D. 24
zlopas [31]

Answer:

I think it's A

I hope this helps

3 0
3 years ago
Read 2 more answers
The results of Accounting Principals’ latest Workonomix survey indicate the average American worker spends $1092 on coffee annua
Nataly_w [17]

Answer:

a)

Group 18-34 years old

\bar x = 1041.625 \\ s^2=485301 \\ s=696.635

Group 35-44 years old

\bar x = 1359.5 \\ s^2=178548 \\ s=422.549

Group 45 and older

\bar x = 1414.375 \\ s^2=18292.27 \\ s=135.248

b)

According to the sample there is 9.04% probability that a person between 18 and 34 consume less than the average, 47.74% probability that a person between 35 and 44 consume more than the average and 50% probability that a person older than 45 consume more than the average.

Step-by-step explanation:

a)

The <em>mean</em> for each sample is

\bar x=\frac{\sum_{k=1}^{10}x_k}{10}

where the x_k are the data corresponding to each group

The <em>variance</em> is

s^2=\frac{\sum_{k=1}^{10}(\bar x-x_k)^2}{9}

and the <em>standard deviation </em>is s, the square root of the variance.

<u>Group 18-34 years old </u>

\bar x = 1041.625 \\ s^2=485301 \\ s=696.635

<u>Group 35-44 years old </u>

\bar x = 1359.5 \\ s^2=178548 \\ s=422.549

<u>Group 45 and older </u>

\bar x = 1414.375 \\ s^2=18292.27 \\ s=135.248

b)

Let's compare these averages against the general media established of $1,092 by using the corresponding z-scores

z=\frac{\bar x-\mu}{s/\sqrt{n}}

where

<em>\bar x = mean of the sample </em>

<em>\mu = established average </em>

<em>s = standard deviation of the sample </em>

<em>n = size of the sample </em>

<u>z-score of Group 18-34 years old </u>

z=\frac{1041.625-1092}{696.635/\sqrt{10}}=-0.2286

The area under the normal curve N(0;1) between -0.2286 and 0 is 0.0904. So according to the sample there is 9.04% probability that a person between 18 and 34 consume less than the average.

<u>z-score of Group 35-44 years old </u>

z=\frac{1359-1092}{422.5491/\sqrt{10}}=2.0019

The area under the normal curve N(0;1) between 0 and 2.0019 is 0.4774. So according to the sample there is 47.74% probability that a person between 35 and 44 consume more than the average.

<u>z-score of Group 45 and older </u>

z=\frac{1414.375-1092}{135.2489/\sqrt{10}}=7.5375

The area under the normal curve N(0;1) between 0 and 7.5375 is 0.5. So according to the sample there is 50% probability that a person older than 45 consume more than the average.

3 0
4 years ago
You have 34 of a pie leftover after your party. Each guest takes home 16 of the leftover pie.
aksik [14]
I believe it is 17/8
6 0
3 years ago
Read 2 more answers
Other questions:
  • Solve the equation by completing the square m^2+6m-77=-5
    12·1 answer
  • Choose the correct slope of the line that passes through the points (1, −3) and (3, −5).
    5·2 answers
  • Mary has 6 pairs of blue pants which represents 40% of slacks in her closet. What is the total number of pants she owns
    13·1 answer
  • on friday the temperature was 82 f the temperature changed by -2 on saturday , and then it changed by 5 on sunday , what was the
    11·1 answer
  • Can someone help its timed
    6·2 answers
  • What two variables are likely to have a negative correlation
    12·1 answer
  • Tell whether the angles are adjacent or vertical. Then find the value of x.
    9·2 answers
  • Find the product and simplify your answer. 7a5(-3a⁴ + 5а - 5 )​
    9·1 answer
  • Does anyone know this answer to the question
    9·2 answers
  • Change 400cm into mm​
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!