All categories

2 years ago

Please help ASAP !!!! Will mark Brainliest

Mathematics

1 answer:

AfilCa [17]2 years ago

3 0

Only multiplication and division don't change the ratio that made the order pairs in the bigger picture the triangle. Only one is not congruent. I'm about 90% sure I got it correct.

You might be interested in

Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v

jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

Step :-(i)

Given x = 1 6 (u + v) …(i)

Differentiating equation (i) partially with respective to 'u'

$\frac{∂x}{∂u} = 16(1)+16(0)=16$

Differentiating equation (i) partially with respective to 'v'

$\frac{∂x}{∂v} = 16(0)+16(1)=16$

Differentiating equation (i) partially with respective to 'w'

$\frac{∂x}{∂w} = 0$

Given y = 1 6 (u − v) …(ii)

Differentiating equation (ii) partially with respective to 'u'

$\frac{∂y}{∂u} = 16(1) - 16(0)=16$

Differentiating equation (ii) partially with respective to 'v'

$\frac{∂y}{∂v} = 16(0) - 16(1)= - 16$

Differentiating equation (ii) partially with respective to 'w'

$\frac{∂y}{∂w} = 0$

Given z = 6uvw ..(iii)

Differentiating equation (iii) partially with respective to 'u'

$\frac{∂z}{∂u} = 6vw$

Differentiating equation (iii) partially with respective to 'v'

$\frac{∂z}{∂v} =6 u (1)w=6uw$

Differentiating equation (iii) partially with respective to 'w'

$\frac{∂z}{∂w} =6 uv(1)=6uv$

Step :-(ii)

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

$\left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|$

Determinant 16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

= -3072uv

Final answer:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

6 0

2 years ago

A mountain in the ocean is bounded by the ocean floor z = 0 and the cone z = 4 − 2 √ x 2 + y 2 . Suppose the heat flow in and ar

Lemur [1.5K]

Answer:

67ft

Step-by-step explanation:

2 s =5 an theres

5 0

3 years ago

Plz, help me with this question!

artcher [175]

Answer:

don't know that sorry can you help me though

3 0

2 years ago

Read 2 more answers

Find the value of the angle θ rounded to 1 DP.

kogti [31]

Answer:

Step-by-step explanation:

Sin 21 = $\frac{opposite side}{hypotenuse}$

Sin 21 = $\frac{BC}{15}$

0.3583 = $\frac{BC}{15}$

0.3583*15 = BC

BC = 5.3745 = 5.37 m

Tan ∅ = $\frac{opposite side}{adjacent side}$

Tan ∅ = $\frac{4}{5.37}= 0.7448$

∅ = tan⁻¹ (0.7448) = 36.67 = 36.7

5 0

2 years ago

Find the volume of the cone. Either enter an exact answer in the terms of pi or use 3.14 for pi

lukranit [14]

Answer:

37.7cm³

Step-by-step explanation:

pi×r² h/3

3.14×2² 9/3

=37.7cm³

4 0

2 years ago