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Total number of times cube was rolled = 100.
Total number of times a 6 was rolled = 27.
Probability of rolling a 6 =
Total number of times coin was tossed = 100.
Total number of times a head was tossed = 41.
Probability of tossing a head =
Therefore, probability of rolling a 6 and tossing a head =
Total number of times a 6 was rolled = 27.
Probability of rolling a 6 =
Total number of times coin was tossed = 100.
Total number of times a head was tossed = 41.
Probability of tossing a head =
Therefore, probability of rolling a 6 and tossing a head =
We will make use of the concept of prime factors for solving this question. The prime factors of 1517 are:
So, as can be clearly seen the Niagara Fall tour operator can either sell 37 tickets for $41 each or 41 tickets for $37 each.
Now, we know that we cannot reach $37 using just three bills. Thus, the only option left to us is $41 which can be broken down into three bills of $20,$20 and $1. This satisfies our condition.
Thus the cost of a ticket was $41 and 37 such tickets were sold.