The area of a right triangle with side lengths 7 and 7 is 
Answer:
<h2><u>0</u></h2>
Step-by-step explanation:
If 2u-6=4, let's solve for u.
Add 6 to both sides
2u-6+6 = 4+6
Simplify
2u = 10
Divide both sides by 2
u = 5
Now, we can solve u-5
5-5 = 0
Answer:
(c) option
Step-by-step explanation:
A = 4pier²
A/4pie = r²
Under root (A/4pie) = r
(c) option
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>
N+1-3n=5+n+1-2
Simplify it
-2n+1 = n+4
Add 2n to both sides
1 = 3n+4
Subtract 4 from both sides
-3 = 3n
Divide by 3
n = -1
we can do this by 2 ways
1- by plotting the points on graph and then tracing the points to get shape,
for linear, we will get straight line
for quadratic, we will get parabola
in this case, it is linear as we get a straight line
2- by solving for values of x and y
consider standard linear equation y = mx +c where m is slope and c is constant
by putting given values of x and y we get
y + 2x = 4(answer)
if we consider standard parabola equation
y^2 = 4ax
this equation is not true for given points
