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Alla [95]
3 years ago
8

What is the area of this composite figure? 12ft2 80 ft2 88 ft2 100 ft2

Mathematics
2 answers:
Julli [10]3 years ago
6 0

Answer:

88

Step-by-step explanation:

just took the test.

iVinArrow [24]3 years ago
5 0
Look at the picture.

x=10ft-2ft=8tf\\\\A_1=10ft\cdot8ft=80ft^2\\\\y=10ft-6ft=4ft\\\\A_2=4ft\cdot2ft=8ft^2\\\\A_F=A_1+A_2\to A_F=80ft^2+8ft^2=88ft^2

Answer:\ \boxed{88ft^2}

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Please help me with this i really need help
kifflom [539]

Answer:

70%

Step-by-step explanation:

The number of students with an April birthday and candles is in the upper left, 14. That’s the “part” Percentage is part/whole x 100.

To figure out the “whole”, you need to add up all the students in the first row of the table, because those are the April birthdays. 14 + 6 = 20

14/20 = 0.7 x 100 = 70%

8 0
3 years ago
What is the area of triangle AED?
Ber [7]

Answer:

Then, the area of the right angle triangle AED is 84in^2.

Step-by-step explanation:

The triangle AED is a right angle triangle

And the area of a triangle is given as

Area=1/2base ×height

The base is 14in

And the height is 12in

Then,

Area=1/2base ×height

Area = 1/2 ×14 ×12

Area = 84in^2

Then, the area of the right angle triangle AED is 84in^2.

8 0
3 years ago
Read 2 more answers
1/4x + 3/4 = 1/2 ??????????
mart [117]

Answer:

x = -1

Step-by-step explanation:

1/2 = 2/4

____________________________________________________________

1/4x + 3/4 = 2/4

<u>         -3/4     -3/4</u>

1/4x = -1/4

divide by -1/4

x = -1

<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>

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4 0
3 years ago
Round to the nearest tenth.
laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

<u />

<u>Recall the Law of Cosines</u>

<u />a^2=b^2+c^2-2bc\cdot cos(A)

<u>Identify angles and sides</u>

<u />m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6

<u>Solve for side "a"</u>

<u />a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2

Therefore, the length of line segment BC is about 8.2 units

8 0
2 years ago
PLEAAASE HELP! i will manifest good things for you. i will mark u brainliest LOL
melamori03 [73]

Answer:

(c) is m=1 i am working on the other ones

5 0
3 years ago
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